Question

我知道这可以使用PHP的parse_url和parse_str函数轻松完成：

$subject = "http://www.youtube.com/watch?v=z_AbfPXTKms&NR=1";
$url = parse_url($subject);
parse_str($url['query'], $query);
var_dump($query);

但如何使用Python实现这一目标？我可以做urlparse，但下一步是什么？

Answer 1

我创建了没有regexp的youtube id解析器：

def video_id(value):
    """
    Examples:
    - http://youtu.be/SA2iWivDJiE
    - http://www.youtube.com/watch?v=_oPAwA_Udwc&feature=feedu
    - http://www.youtube.com/embed/SA2iWivDJiE
    - http://www.youtube.com/v/SA2iWivDJiE?version=3&amp;hl=en_US
    """
    query = urlparse(value)
    if query.hostname == 'youtu.be':
        return query.path[1:]
    if query.hostname in ('www.youtube.com', 'youtube.com'):
        if query.path == '/watch':
            p = parse_qs(query.query)
            return p['v'][0]
        if query.path[:7] == '/embed/':
            return query.path.split('/')[2]
        if query.path[:3] == '/v/':
            return query.path.split('/')[2]
    # fail?
    return None

Answer 2

Python有a library for parsing URLs。

import urlparse
url_data = urlparse.urlparse("http://www.youtube.com/watch?v=z_AbfPXTKms&NR=1")
query = urlparse.parse_qs(url_data.query)
video = query["v"][0]

Answer 3

以下是RegExp，它涵盖了这些案例 enter image description here

((?<=(v|V)/)|(?<=be/)|(?<=(\?|\&)v=)|(?<=embed/))([\w-]+)

Answer 4

match = re.search(r"youtube\.com/.*v=([^&]*)", "http://www.youtube.com/watch?v=z_AbfPXTKms&test=123")
if match:
    result = match.group(1)
else:
    result = ""

未测试。

Answer 5

不需要正则表达式。在?上拆分，取第二个，在=上拆分，取第二个，在&上拆分，取第一个。

Answer 6

您可以尝试使用正则表达式获取YouTube视频ID：

# regex for the YouTube ID: "^[^v]+v=(.{11}).*"
result = re.match('^[^v]+v=(.{11}).*', url)
print result.group(1)

Answer 7

您可以使用

from urllib.parse import urlparse

url_data = urlparse("https://www.youtube.com/watch?v=RG9TMn1FJzc")
print(url_data.query[2::])

Answer 8

当这些参数可以按任何顺序出现时，拆分字符串是一个非常糟糕的主意。坚持使用 urlparse：

from urllib.parse import parse_qs, urlparse

vid = parse_qs(urlparse(url).query).get('v')

Answer 9

我使Mikhail Kashkin的解决方案对Python3友好

from urllib.parse import urlparse

def video_id(url):
    """
    Examples:
    - http://youtu.be/SA2iWivDJiE
    - http://www.youtube.com/watch?v=_oPAwA_Udwc&feature=feedu
    - http://www.youtube.com/embed/SA2iWivDJiE
    - http://www.youtube.com/v/SA2iWivDJiE?version=3&amp;hl=en_US
    """
    o = urlparse(url)
    if o.netloc == 'youtu.be':
        return o.path[1:]
    elif o.netloc in ('www.youtube.com', 'youtube.com'):
        if o.path == '/watch':
            id_index = o.query.index('v=')
            return o.query[id_index+2:id_index+13]
        elif o.path[:7] == '/embed/':
            return o.path.split('/')[2]
        elif o.path[:3] == '/v/':
            return o.path.split('/')[2]
    return None  # fail?

Answer 10

尽管这将进行搜索查询，但会给您id：

from youtube_search import YoutubeSearch    
results = YoutubeSearch('search terms', max_results=10).to_json()    
print(results)

Answer 11

url = "http://www.youtube.com/watch?v=z_AbfPXTKms&NR=1"
parsed = url.split("?")
videoId = parsed[1]
print(videoId)

这将适用于各种YouTube视频链接。

Answer 12

我使用这个很棒的包 pytube。$ pip install pytube

#Examples
url1='http://youtu.be/SA2iWivDJiE'
url2='http://www.youtube.com/watch?v=_oPAwA_Udwc&feature=feedu'
url3='http://www.youtube.com/embed/SA2iWivDJiE'
url4='http://www.youtube.com/v/SA2iWivDJiE?version=3&amp;hl=en_US'
url5='https://www.youtube.com/watch?v=rTHlyTphWP0&index=6&list=PLjeDyYvG6-40qawYNR4juzvSOg-ezZ2a6'
url6='youtube.com/watch?v=_lOT2p_FCvA'
url7='youtu.be/watch?v=_lOT2p_FCvA'
url8='https://www.youtube.com/watch?time_continue=9&v=n0g-Y0oo5Qs&feature=emb_logo'

urls=[url1,url2,url3,url4,url5,url6,url7,url8]

#Get youtube id
from pytube import extract
for url in urls:
    id=extract.video_id(url)
    print(id)

输出

SA2iWivDJiE
_oPAwA_Udwc
SA2iWivDJiE
SA2iWivDJiE
rTHlyTphWP0
_lOT2p_FCvA
_lOT2p_FCvA
n0g-Y0oo5Qs

Answer 13

我迟到了，但我使用这个片段来获取视频 ID。

def video_id(url: str) -> str:
    """Extract the ``video_id`` from a YouTube url.
    This function supports the following patterns:
    - :samp:`https://youtube.com/watch?v={video_id}`
    - :samp:`https://youtube.com/embed/{video_id}`
    - :samp:`https://youtu.be/{video_id}`
    :param str url:
        A YouTube url containing a video id.
    :rtype: str
    :returns:
        YouTube video id.
    """
    return regex_search(r"(?:v=|\/)([0-9A-Za-z_-]{11}).*", url, group=1)

def regex_search(pattern: str, string: str, group: int):
    """Shortcut method to search a string for a given pattern.
    :param str pattern:
        A regular expression pattern.
    :param str string:
        A target string to search.
    :param int group:
        Index of group to return.
    :rtype:
        str or tuple
    :returns:
        Substring pattern matches.
    """
    regex = re.compile(pattern)
    results = regex.search(string)
    if not results:
        return False

    return results.group(group)

如何从Python的YouTube链接中提取视频ID？

13 个答案: