我目前正在使用SQL Server 2012上的T-SQL中的选择查询。这是一个复杂的查询,我想查询3个表中的列表。结果应如下所示:
期望输出:
ProjectId | Title | Manager | Contact | StatusId
----------+-------------+-----------+-----------+-----------
1 | projectX | 1123 | 4453 | 1
2 | projectY | 2245 | 5567 | 1
3 | projectZ | 3335 | 8899 | 1
我的3张桌子:
1)项目: ProjectId,ProjectDataId,MemberVersionId
2) ProjectData: ProjectDataId,Title,StatusId
3)成员: MemberId,MemberVersionId,MemberTypeId,EmployeeId
棘手的部分是实现版本控制。因此,随着时间的推移,项目成员可以更改,并且应该始终可以返回到以前的版本,这就是为什么我在 Project 和<之间使用 MemberVersionId 作为外键的原因EM>成员。表Project和ProjectData与ProjectDataId链接。
因此,1个项目有1个OfferData,1个项目有N个成员。
一些样本数据:
项目
ProjectId | ProjectDataId | MemberVersionId |
----------+---------------+-----------------+
1 | 2 | 1 |
2 | 3 | 1 |
3 | 4 | 1 |
ProjectData的
ProjectDataId | Title | StatusId
--------------+-------------+-----------
2 | projectX | 1
3 | projectY | 1
4 | projectZ | 1
成员: MemberTypeId 1 =经理,MemberTypeId 2 =联系人,3 =其他
MemberId | MemberVersionId | MemberTypeId | EmployeeId |
---------+-----------------+--------------+------------+
1 | 1 | 1 | 1123 |
2 | 1 | 2 | 4453 |
3 | 1 | 3 | 9999 |
4 | 2 | 1 | 2245 |
5 | 2 | 2 | 5567 |
6 | 2 | 3 | 9999 |
7 | 3 | 1 | 3335 |
8 | 3 | 2 | 8899 |
9 | 3 | 3 | 9999 |
我当前的查询如下所示:
SELECT ProjectId, Title, EmployeeId AS Manager, EmployeeId AS Contact, StatusId
FROM [MySchema].[Project] a,
[MySchema].[ProjectData] b,
[MySchema].[Members] c
WHERE a.ProjectDataId = b.ProjectDataId
AND a.MemberVersionId = c.MemberVersionId
不幸的是,这还不行。你知道如何解决这个问题吗?
由于
答案 0 :(得分:4)
这样的东西?
SELECT
p.ProjectId,
pd.Title,
mm.EmployeeId AS Manager,
mc.EmployeeId AS Contact,
pd.StatusId
FROM
[MySchema].[Project] p
INNER JOIN [MySchema].[ProjectData] pd ON pd.ProjectDataId = p.ProjectDataId
INNER JOIN [MySchema].[Members] mm ON mm.MemberVersionId = p.MemberVersionId AND mm.MemberTypeId = 1
INNER JOIN [MySchema].[Members] mc ON mc.MemberVersionId = p.MemberVersionId AND mc.MemberTypeId = 2;
答案 1 :(得分:2)
你可以试试这个:
SELECT ProjectId, Title, C.EmployeeId AS Manager, d.EmployeeId AS Contact, StatusId
FROM [MySchema].[Project] a
INNER JOIN [MySchema].[ProjectData] b ON A.ProjectDataId=B.ProjectDataId
LEFT JOIN (SELECT * FROM [MySchema].[Members] WHERE MemberTypeID=1) c ON a.MemberVersionId=c.MemberVersionId
LEFT JOIN (SELECT * FROM [MySchema].[Members] WHERE MemberTypeID=2) d ON a.MemberVersionId=d.MemberVersionId
答案 2 :(得分:2)
您必须两次选择成员,一个用于经理,另一个用于联系:
SELECT ProjectId, Title, m.EmployeeId AS Manager, c.EmployeeId AS
Contact, StatusId
FROM [MySchema].[Project] a,
[MySchema].[ProjectData] b,
[MySchema].[Members] m
[MySchema].[Members] c
WHERE a.ProjectDataId = b.ProjectDataId
AND a.MemberVersionId = m.MemberVersionId and m.MemberTypeId = 1
AND a.MemberVersionId = c.MemberVersionId and c.MemberTypeId = 2
答案 3 :(得分:2)
试试这个,
SELECT ProjectId, Title, cmanager.EmployeeId AS Manager, ccon.EmployeeId AS
Contact, StatusId
from [MySchema].[ProjectData] b
inner join [MySchema].[Project] a on b.ProjectDataId=a.ProjectDataId
left join [MySchema].[Members] cmanager on cmanager.MemberVersionId =
a.MemberVersionId and cmanager.MemberTypeId=1
left join [MySchema].[Members] ccon on ccon.MemberVersionId =
a.MemberVersionId and ccon.MemberTypeId=2
答案 4 :(得分:2)
解决问题的最简单方法是在Project
表中引入其他字段。您可以将其称为LatestMemberVersion
(int,保持当前最高的MemberVersionId),这将是最新版本的关系,您可以添加更简单的IsLatestMemberVersion
(位,保持1如果记录是最新的/活动的)。您可以使用ROW_NUMBER() OVER
语句计算它们。
然后,查询将更改为:
SELECT ProjectId, Title, EmployeeId AS Manager, EmployeeId AS Contact, StatusId
FROM [MySchema].[Project] a,
[MySchema].[ProjectData] b ON a.ProjectDataId = b.ProjectDataId
[MySchema].[Members] c ON a.MemberVersionId = c.MemberVersionId
WHERE
a.[IsLatestMemberVersion] = 1 -- alternative is a.[LatestMemberVersion] = a.[MemberVersionId]
此外,您还可以尝试两件事:
您可能想借用数据仓库的想法,即您希望将慢速变化维度类型1和2的组合
您可以尝试使用SQL Server功能,例如更改数据跟踪。但我没有这方面的经验,所以它可能无处可去。
最后一条建议,如果可以的话,永远不要在WHERE子句中写入连接条件。当您突然将JOIN更改为LEFT JOIN时,它不可读并且可能导致问题。 Microsoft本身建议在适用时使用ON
而不是WHERE
。