Question

如果有人可以提供帮助，我会很感激。我有两张没有关系的桌子：

TABLE_1

ID    NAME    VALUE
1     abc     10
2     def     20
3     def     20

TABLE_2

   ID2    NAME2    VALUE2
    5     ghi     30
    6     gkl     40

我想要一个select语句，它将显示来自两个表的数据：

   ID    NAME    VALUE  ID2   NAME2   VALUE2
    1     abc     10    5     ghi     30
    2     def     20    6     gkl     40
    3     def     20

重点是在一行中显示每条记录的数据，表格如下：

 ID    NAME    VALUE  ID2   NAME2   VALUE2
                      5     ghi     30
                      6     gkl     40

如果Table_1没有记录。 Table_2也是如此。我尝试使用交叉连接，但随后数据将重复。

非常感谢

Answer 1

您需要添加join条件。在这种情况下，通过使用row_number()在每一侧添加序号。然后full outer join获取所有记录：

select t1.id, t1.name, t1.value, t2.id as id2, t2.name as name2, t2.value as value2
from (select t1.*, row_number() over (order by id) as seqnum
      from table_1 t1
     ) t1 full outer join
     (select t2.*, row_number() over (order by id) as seqnum
      from table_2 t2
     ) t2
     on t1.seqnum = t2.seqnum;

Answer 2

试试这个：

with Table_1(ID, NAME, VALUE) as (
  select 1, 'abc', 10 union all
  select 2, 'def', 20 union all
  select 3, 'def', 20
), Table_2(ID2, NAME2, VALUE2) as (
  select 5, 'ghi', 30 union all
  select 6, 'gkl', 40
), prep_table_1 (ID, NAME, VALUE, rn) as (
  select id, name, value, row_number() over(order by id)
    from table_1
), prep_table_2 (ID2, NAME2, VALUE2, rn) as (
  select id2, name2, value2, row_number() over(order by id2)
    from table_2
)
select t1.ID, t1.NAME, t1.VALUE, t2.ID2, t2.NAME2, t2.VALUE2
  from prep_table_1 t1
  full outer join prep_table_2 t2 on t1.rn = t2.rn

SQLFiddle

Answer 3

这也有效

从Table_1，Table_2中选择*

从没有连接条件的两个表中选择数据，t-sql

3 个答案: