Question

在Julia，我想将定义为2D数组的Vector的数据转换为Matrix的2D数组。如下例所示，我想将数据转换为数据t，但到目前为止我还没有成功。我应该如何处理此案？

julia> s = [[1 2 3], [4 5 6], [7 8 9]]
3-element Array{Array{Int64,2},1}:
 [1 2 3]
 [4 5 6]
 [7 8 9]

julia> t = [[1 2 3]; [4 5 6]; [7 8 9]]
3××3 Array{Int64,2}:
 1  2  3
 4  5  6
 7  8  9

julia> s |> typeof
Array{Array{Int64,2},1}

julia> t |> typeof
Array{Int64,2}

julia> convert(Array{Int64, 2}, s)
ERROR: MethodError: Cannot `convert` an object of type Array{Array{Int64,2},1} to an object of type Array{Int64,2}
This may have arisen from a call to the constructor Array{Int64,2}(...),
since type constructors fall back to convert methods.

julia> reshape(s, 3, 3)
ERROR: DimensionMismatch("new dimensions (3,3) must be consistent with array size 3")
 in reshape(::Array{Array{Int64,2},1}, ::Tuple{Int64,Int64}) at .\array.jl:113
 in reshape(::Array{Array{Int64,2},1}, ::Int64, ::Int64, ::Vararg{Int64,N}) at .\reshapedarray.jl:39

如下例所示，如果您将2D数组或1D数组定义为源数据，我可以将它们成功地重塑为Matrix的2D数组。

julia> u = [1 2 3 4 5 6 7 8 9]
1××9 Array{Int64,2}:
 1  2  3  4  5  6  7  8  9

julia> u |> typeof
Array{Int64,2}


julia> reshape(u, 3, 3)
3××3 Array{Int64,2}:
 1  4  7
 2  5  8
 3  6  9



julia> v = [1, 2, 3, 4, 5, 6, 7, 8, 9]
9-element Array{Int64,1}:
 1
 2
 3
 4
 5
 6
 7
 8
 9

julia> v  |> typeof
Array{Int64,1}

julia> reshape(v, 3, 3)
3××3 Array{Int64,2}:
 1  4  7
 2  5  8
 3  6  9

Answer 1

您可以使用vcat和splatting

julia> t = vcat(s...)
3×3 Array{Int64,2}:
 1  2  3
 4  5  6
 7  8  9

如何转换Array {Array {Int64,2}，1}到Array {Int64,2}

1 个答案: