Question

我有一个场景，其中有一个高价值的LOV作为＆＃34;包＆＃34;和TYPE =＆＃34; TO_NEW_PACKAGE＆＃34;我必须获取Low的值，Low中有8个记录。我必须显示每条记录的所有8条记录及其组件成本。所有这些应该作为显示消息将被输出。请让我知道如何做到这一点。

var sSearchExp =＆＃34; [Type] =＆＃39;＆＃34; +＆＃34; PACKAGE_PLAN＆＃34; +＆＃34;＆＃39; AND [高] =＆＃39;＆＃34; + PACKAGEPLAN +＆＃34;＆＃39;＆＃34 ;; SetSearchExpr（sSearchExp）;的executeQuery（）; var isRecord = FirstRecord（）; while（isRecord）{Slow = GetFieldValue（＆＃34; Low＆＃34;）; Outputs.SetProperty（＆＃34; NEW_PACKAGE_PLAN＆＃34;，Slow）; Outputs.SetProperty（＆＃34; ErrorCode＆＃34;，＆＃34; 00＆＃34;）; Outputs.SetProperty（＆＃34; ErrorDesc＆＃34;，＆＃34; Success＆＃34;）; i = i + 1; isRecord = NextRecord（）; }

这只存储了1条记录...我想要显示所有8条记录！

Answer 1

这应该让你入门

var sSearchExp = "[Type]= '" + "PACKAGE_PLAN" + "' AND [High] = '" + PACKAGEPLAN + "'";
var Slow = "";
SetSearchExpr(sSearchExp);
ExecuteQuery();
var isRecord = FirstRecord();
while (isRecord) {
    Slow += GetFieldValue("Low");
    Slow += " ";
    i = i + 1;
    isRecord = NextRecord();
}
Outputs.SetProperty("NEW_PACKAGE_PLAN", Slow);
Outputs.SetProperty("ErrorCode", "00");
Outputs.SetProperty("ErrorDesc", "Success");

Answer 2

此示例代码将向下打印值：

var boAsset = TheApplication().GetBusObject("List Of Values");
var bcAsset = boAsset.GetBusComp("List Of Values");

with (bcAsset)
{
    ActivateField("Value");
    var sSearchExp = "[Type]= 'AAG_TABLE_TYPE'";
    var Slow = "";
    SetSearchExpr(sSearchExp);
    ExecuteQuery();
    var isRecord = FirstRecord();
    while (isRecord)
    {
        Slow += GetFieldValue("Value");
        Slow += "\n";
        isRecord = NextRecord();
    }
    TheApplication().RaiseErrorText(Slow);
}

输出：

AAG Account
AAG Holdg
AAG Portf
AAG Txn

将Slow += "\n";更改为Slow += " ";会将值打印到侧面。

希望你能在这里得到诀窍。

如何在siebel中的BS中编写脚本以在输出中存储多个记录？

2 个答案: