Question

这是给出的任务：

对于此作业，您将从作业1更新时间类。要开始，您可以复制作业1 Time.java，或下载解决方案Time.java。首先，您需要更新Time以便它实现Comparable接口。这将需要在类声明和compareTo方法中添加一个implements语句。然后，您需要在类中添加差异方法。这两种方法＆＃39;要求如下：

   compareTo(Object other)
     //Returns -1 if current time is less than other.
        //Returns 0 if current time is equal to other.
        //Returns 1 if current time is greater than other.

String difference(Time t)
    //Returns a String holding the difference between the current time and 
    //the Time t passed in via parameter. All values should be positive, 
    //and in the format: 
    //Time difference: 08:09 
    //Time difference: 10:35

要测试代码，请下载并运行runner类：student_runner_time.java。我们将使用不同但相似的测试类来对程序进行评分。您需要更改运行器以使用其他值进行测试，以确保您的程序符合所有要求。

 Sample Run of student_runner_time.java:
    1712
    0945
    Greater than:
    1
    Less than:
    -1
    Times equal:
    0
    Hours equal:
    1
    -1
    Difference
    Time difference: 00:11
    Time difference: 00:11
    Time difference: 00:00

注意：您必须使用班级名称＆＃34;时间＆＃34;这项任务。请记住：您必须提交您的答案。除非已提交，否则您的作业不会被视为完成。

这是我提交的内容：

public class Time implements Comparable<Time> {
  private int hour;
  private int minute;
  /*
Sets the default time to 12:00.
*/
  public Time() {
    this(12, 0);
  }
  /*
Sets hour to h and minute to m.
*/
  public Time(int h, int m) {
    hour = 0;
    minute = 0;
    if (h >= 1 && h <= 23)
      hour = h;
    if (m >= 1 && m <= 59)
      minute = m;
  }
  /*
Returns the time as a String of length 4 in the format: 0819.
*/
  public String toString() {
    String h = "";
    String m = "";
    if (hour < 10)
      h += "0";
    if (minute < 10)
      m += "0";
    h += hour;
    m += minute;
    return "" + h + "" + m;
  }
  public String difference(Time that) {
    int thisMin = this.hour * 60 + this.minute;
    int thatMin = that.hour * 60 + that.minute;
    int diffMin = Math.abs(thisMin - thatMin);
    int diffH = diffMin / 60;
    int diffM = diffMin % 60;
    String h = "";
    String m = "";
    if (diffH < 10) {
      h += "0";
    }
    if (diffM < 10) {
      m += "0";
    }
    h += diffH;
    m += diffM;
    return h + ":" + m;
  }
  @Override
  public int compareTo(Time that) {
    int thisMin = this.hour * 60 + this.minute;
    int thatMin = that.hour * 60 + that.minute;
    if (thisMin < thatMin) {
      return -1;
    } else if (thisMin > thatMin) {
      return 1;
    } else {
      return 0;
    }
  }
}

这些是我收到的错误：

您的代码已根据一组测试数据进行评估你有7个测试中的3个正确通过。
你的分数是42％。

失败的测试是：

Test2: difference()
    Incorrect: First Time Less
    Incorrect: First Time Greater
    Incorrect: Large Difference
    Incorrect: Small Difference

需要有关标题为：Time Comparable的Java任务的帮助

0 个答案: