Question

说我有一块异常声明：

try:
    expression
except err1:
    #process error
    ...
    ...
except err10:
    #process error

如果引发任何异常，我想调用sys.exit(1)。我是否必须在每个子块中手动调用它，或者是否有内置方式来声明类似于：

    ...
except err10:
    #process error
"if any of these exception were raised":
    sys.exit(1)

Answer 1

你可以做的一件事是：

flag = False

try:
    expression
    flag = True
except err1:
    #process error
    ...
    ...
except err10:
    #process error
if not flag:
    sys.exit(1) #exit program

如果该标志为False，则表示您没有通过try循环，因此引发了错误。

Answer 2

在Python中，有一个可选的else块，在没有引发异常的情况下执行。您可以使用它为您的代码设置一个标志，并将代码从try/except块中退出：

is_exception = True

try:
    expression
except err1:
    # ... something
except err10:
    # ... something else
else:
    # This will be executed if there is no exception
    is_exception = False

if is_exception:
    sys.exit(1)

Answer 3

raised = True
try:
    expression
except err1:
    # process error
    raise

...

except err10:
    # process error
    raise
else:
    # if no error was raised
    raised = False
finally:
    if raised:
        raise SystemExit

Answer 4

以下是我在评论中谈到的内容：

for u,v,d in g.edges():
    d['weight'] = 1
g.edges(data=True)
edges = g.edges()
weights = [g[u][v]['weight'] for u,v in edges]

如果引发/捕获任何异常，如何有效地退出python程序

4 个答案: