Question

我正在尝试测试我的身份验证失败。引发了异常，但未被assertRaises捕获。我在这里想念什么？

def test_auth(self):
    from graphql_jwt.exceptions import PermissionDenied

    with self.assertRaises(PermissionDenied):
        response = self.client.execute(self.query)

跟踪：

Creating test database for alias 'default'...
System check identified no issues (0 silenced).
Traceback (most recent call last):
  File "/home/dan/game/venv/lib/python3.7/site-packages/promise/promise.py", line 487, in _resolve_from_executor
    executor(resolve, reject)
  File "/home/dan/game/venv/lib/python3.7/site-packages/promise/promise.py", line 754, in executor
    return resolve(f(*args, **kwargs))
  File "/home/dan/game/venv/lib/python3.7/site-packages/graphql/execution/middleware.py", line 75, in make_it_promise
    return next(*args, **kwargs)
  File "/home/dan/game/venv/lib/python3.7/site-packages/graphene_django/filter/fields.py", line 106, in connection_resolver
    **args
  File "/home/dan/game/venv/lib/python3.7/site-packages/graphene_django/fields.py", line 156, in connection_resolver
    iterable = resolver(root, info, **args)
  File "/home/dan/game/venv/lib/python3.7/site-packages/graphql_jwt/decorators.py", line 31, in wrapper
    return func(info.context, *args, **kwargs)
  File "/home/dan/game/venv/lib/python3.7/site-packages/graphql_jwt/decorators.py", line 43, in wrapper
    raise exceptions.PermissionDenied()
graphql.error.located_error.GraphQLLocatedError: You do not have permission to perform this action

F.
======================================================================
FAIL: test_auth (api.tests.test_mutations.TestGame)
----------------------------------------------------------------------
Traceback (most recent call last):
  File "/home/dan/game/api/tests/test_mutations.py", line 57, in test_auth
    response = self.client.execute(self.query)
AssertionError: PermissionDenied not raised

正在引发异常here。

Answer 1

您的测试未捕获到PermissionDenied异常，因为正在运行的代码中的某些内容将该异常包装在graphql.error.located_error.GraphQLLocatedError的实例中。因为您要检查错误的异常类型，所以测试失败。

我对所使用的库不了解太多，并且异常类型的无形更改似乎具有可怕的错误功能（它至少应将用于更改异常类型的代码添加到异常回溯中）因此您可以对其进行调试）。但是，您可以通过捕获包装的异常并重新抛出原始异常来解决此问题：

def test_auth(self):
    from graphql_jwt.exceptions import PermissionDenied
    from graphql.error.located_error import GraphQLLocatedError

    with self.assertRaises(PermissionDenied):
        try:
            response = self.client.execute(self.query)
        except GraphQLLocatedError as e:
            raise e.original_error

Answer 2

根据定义，

GraphQL捕获所有异常并将错误放入响应的错误部分。如果要测试查询（self.client.execute（... query ...））的执行情况，则应获取结果并验证其错误部分与您的期望相符。

一种更简单的方法是专门测试解析器-直接而不是通过GraphQL执行层调用resolve_entity，然后像测试其他Python函数一样对其进行测试。

引发异常但未被assertRaises捕获

2 个答案: