Question

这是以下问题的后续问题：Rowsums conditional on column name

我的数据框名为wiod，如下所示：

VAR1 VAR2 AUS1 ... AUS56 BEL1 ... BEL56 NLD1 ... NLD56
A    D    23   ... 99    0    ... 444   123  ... 675
B    D    55   ... 6456  0    ... 557   567  ... 4345

我想计算变量AUS, BEL, NLD的行和，然后删除旧变量。像这样：

wiot <- wiot %>% 
  mutate(AUS = rowSums(.[grep("AUS", names(.))])) %>% 
  mutate(BEL = rowSums(.[grep("BEL", names(.))])) %>% 
  mutate(NLD = rowSums(.[grep("NLD", names(.))])) %>% 
  select(Var1, Var2, AUS, BEL, NLD)

当然，有大量的变量组，而不仅仅是这三个（准确地说是43）。没有使用43个mutate命令，有没有方便的方法呢？

Answer 1

它可以更容易地从宽格式转换为长格式（聚集），然后进行汇总，如果需要，还可以转换回广泛（传播）格式：

library(dplyr)
library(tidyr)

# dataframe from @989 http://stackoverflow.com/a/43519062
df1 %>% 
  gather(key = myKey, value = myValue, -c(VAR1, VAR2)) %>% 
  mutate(myGroup = gsub("\\d", "", myKey)) %>% 
  group_by(VAR1, VAR2, myGroup) %>% 
  summarise(mySum = sum(myValue)) %>% 
  spread(key = myGroup, value = mySum)

# Source: local data frame [2 x 5]
# Groups: VAR1, VAR2 [2]
# 
#     VAR1   VAR2   AUS   BEL   NLD
# * <fctr> <fctr> <int> <int> <int>
# 1      A      D   122   444   798
# 2      B      D  6511   557  4912

Answer 2

你可以试试这个：

vec <- c("AUS", "BEL", "NLD")
cbind(df[,grep("VAR", names(df))], 
      sapply(vec, function(x) rowSums(df[,grep(x, names(df))])))

#  VAR1 VAR2  AUS BEL  NLD
#1    A    D  122 444  798
#2    B    D 6511 557 4912

您只需要使用43个变量加载vec。

数据

df <- structure(list(VAR1 = structure(1:2, .Label = c("A", "B"), class = "factor"), VAR2 = structure(c(1L, 1L), .Label = "D", class = "factor"), AUS1 = c(23L, 55L), AUS56 = c(99L, 6456L), BEL1 = c(0L, 0L ), BEL56 = c(444L, 557L), NLD1 = c(123L, 567L), NLD56 = c(675L, 4345L)), .Names = c("VAR1", "VAR2", "AUS1", "AUS56", "BEL1", "BEL56", "NLD1", "NLD56"), class = "data.frame", row.names = c(NA, -2L))

Answer 3

这是另一个使用tidyverse功能但没有gather

的版本

library(tidyverse)
fSumN1 <- function(dat, pat){
      pat1 <- paste(pat, collapse="|")
      newN <- paste0(pats, "_sum")
      dat1 <- dat %>%
                  select(-matches(pat1))
      dat %>%
           select(matches(pat1)) %>%
           split.default(sub("\\d+", "", names(.))) %>%
           map_df(rowSums) %>%
           rename_at(.vars = pat, funs(paste0(pat, "_sum"))) %>%
           bind_cols(dat1, .)

 }



pats <- c("AUS", "AUT")
fSumN1(dfN, pats)
#  VAR1 VAR2 VAR3 VAR4 AUS_sum AUT_sum
#1    A    D    0  FCK    1246    3076
#2    B    D    0  XYC    6678    3349

数据

dfN <- structure(list(VAR1 = c("A", "B"), VAR2 = c("D", "D"), AUS1 = c(23L, 
55L), AUS2 = c(234L, 76L), AUS3 = c(34L, 55L), AUS4 = c(856L,  
36L), AUS56 = c(99L, 6456L), VAR3 = c(0L, 0L), VAR4 = c("FCK", 
"XYC"), AUT1 = c(598L, 774L), AUT2 = c(992L, 503L), AUT3 = c(819L, 
944L), AUT4 = c(368L, 717L), AUT56 = c(299L, 411L)), .Names = c("VAR1", 
"VAR2", "AUS1", "AUS2", "AUS3", "AUS4", "AUS56", "VAR3", "VAR4", 
"AUT1", "AUT2", "AUT3", "AUT4", "AUT56"), row.names = c(NA, -2L
), class = "data.frame")

Rowsums以循环中的列名为条件

3 个答案:

数据