Question

我有一个表partywise_account_ledger，其中包含name_of_the_customer，invoice_date和invoice_value列。我想根据天数检索invoice_value。要获取< 5 days的值，我使用查询：

select name_of_the_customer, sum(invoice_value)
from partywise_accounts_ledger
where datediff(d, invoice_date, '2017-04-19') < 5
group by name_of_the_customer

This is the Result of the Query

如何将< 10 days列附加到其中并在单个语句中显示？

谢谢！

Answer 1

将case表达式用于条件聚合：

select name_of_the_customer,
       sum(case when datediff(d, invoice_date, '2017-04-19') < 5 then invoice_value end),
       sum(case when datediff(d, invoice_date, '2017-04-19') < 10 then invoice_value end)
from partywise_accounts_ledger
where datediff(d, invoice_date, '2017-04-19') < 10
group by name_of_the_customer

第二个SUM()（适用于<10天），可以简化为sum(invoice_value)。

如何获取列记录sql中两个日期之间的天数

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