我试图注册同一个类的多个实例,这样当我注入该类的可枚举时,我会检索所有实例。
public class ActionDialogType
{
public Type Type { get; set; }
public string Name { get; set; }
}
public class ActionDialogTypeUser
{
private IEnumerable<ActionDialogType> _types;
public ActionDialogTypeUser(IEnumerable<ActionDialogType> types)
{
_types = types
}
public void DoSomethingWithTypes()
{
// Do Something with types
}
}
到目前为止我已经:
public class UnityConfig
{
public IUnityContainer Register()
{
UnityContainer container = new UnityContainer();
ActionDialogType actionDialogType1 = new ActionDialogType
{
Name = "Something",
Type = typeof(Something)
};
container.RegisterInstance<IActionDialogType>(actionDialogType1, new ContainerControlledLifetimeManager());
ActionDialogType actionDialogType2 = new ActionDialogType
{
Name = "SomethingElse",
Type = typeof(SomethingElse)
};
container.RegisterInstance<ActionDialogType>(actionDialogType2, new ContainerControlledLifetimeManager());
container.RegisterType<IEnumerable<ActionDialogType>, ActionDialogType[]>();
return container;
}
}
有人能告诉我怎么做吗?
答案 0 :(得分:3)
只需使用名称注册依赖关系,然后解决:
...
container.RegisterInstance<IActionDialogType>("actionDialogType1", actionDialogType1, new ContainerControlledLifetimeManager());
...
container.RegisterInstance<IActionDialogType>("actionDialogType2", actionDialogType2, new ContainerControlledLifetimeManager());
var actionDialogTypeUser = container.Resolve<ActionDialogTypeUser>();
构造函数也应该具有相同的类型(在您的情况下为接口):
public ActionDialogTypeUser(IEnumerable<IActionDialogType> types)
{
_types = types
}
答案 1 :(得分:0)
您应该能够通过以下方式解析IEnumerable
个依赖项:
container.RegisterType<IEnumerable<IActionDialogType>, IActionDialogType[]>();
由于Unity了解数组,因此您只需将可枚举数据映射到相同类型的数组即可。这将允许您返回实例的可枚举。
然后您可以简单地执行以下操作:
public class ExampleController : Controller
{
private readonly IEnumerable<IActionDialogType> actionDialogType;
public ExampleController(IActionDialogType actionDialogType)
{
this.actionDialogType = actionDialogType;
}
public IActionResult Get()
{
foreach(IActionDialogType instance in actionDialogType)
{
// Should expose via each now.
var name = instance.GetType().Name;
}
}
}