SQL显示当前年份的所有周(52)

时间:2017-04-19 11:39:41

标签: mysql sql mariadb

如何在当前

中显示所有周(52)

我提出了这个问题:

SELECT 
    COALESCE(IF(DATE_FORMAT(q.date_add, '%Y-%u') IS NULL,
                (DATE_FORMAT(q.date_add, '%Y-%u')),
                DATE_FORMAT(q.date_add, '%Y WEEK %u'))) AS CurrentDate,
    COALESCE(IF(SUM(q.totalExcl) IS NULL,
                0,
                SUM(q.totalExcl))) AS total
FROM
    expoled.ps_oxoquotation_quotationstate_history h
        RIGHT JOIN
    expoled.ps_oxoquotation_quotation q ON h.idQuotation = q.idQuotation
        LEFT JOIN
    expoled.ps_employee e ON h.idEmployee = e.id_employee
        INNER JOIN
    expoled.ps_sv_employee_meta m ON h.idEmployee = m.id_employee
WHERE
    h.idEmployee = 39
        AND YEAR(q.date_add) = YEAR(UTC_TIMESTAMP())
        AND h.idQuotationState = 3
GROUP BY IFNULL(CurrentDate, '')

我想我需要在这里做点什么:

SELECT 
    IFNULL(DATE_FORMAT(q.date_add, '%Y WEEK %u'), 0) AS CurrentDate,
    IFNULL(SUM(q.totalExcl),0) AS total
FROM

我已经尝试过放置IFNULL,但这给了我相同的结果

这就是我现在所得到的:

enter image description here

显示当前几周从5周到16周。 第1周到第4周也没有任何内容,因为没有数据。而且它只需显示一个简单的零(0)

所以我想要的是它需要从第1周到第52周显示标准,如果没有数据只是0

该查询现在正常运行,没有任何错误。

2 个答案:

答案 0 :(得分:1)

为了获得固定的周数,没有特定的表,我尝试了这个。 表XX1只是为了进行测试,可以用你的一个表替换。如果它有多个记录> = 366,你可以消除CROSS JOIN。

CREATE TABLE XX1 (id INT);
INSERT INTO XX1 VALUES (1);
INSERT INTO XX1 VALUES (2);
INSERT INTO XX1 VALUES (3);
INSERT INTO XX1 VALUES (4);
INSERT INTO XX1 VALUES (5);

SELECT DISTINCT DATE_FORMAT(RN, '%Y w%u') AS CURR_WEEK
FROM 
  (SELECT @RN:=DATE_ADD(str_to_date(  CONCAT(YEAR(UTC_TIMESTAMP()) ,'0101'), '%Y%m%d'), INTERVAL -1 DAY) AS RN
   UNION ALL 
   SELECT @RN:=DATE_ADD(@RN, INTERVAL 1 DAY) AS RN 
   FROM (SELECT 1 AS DUM FROM XX1
           CROSS JOIN XX1 X2
           CROSS JOIN XX1 X3
           CROSS JOIN XX1 X4
         ) Y LIMIT 366
   ) X
   WHERE YEAR(RN)=YEAR(UTC_TIMESTAMP())
   ORDER BY 1;
DROP TABLE XX1 ;

输出:

    CURR_WEEK
1   2017 w00
2   2017 w01
3   2017 w02
4   2017 w03
5   2017 w04
...
51  2017 w50
52  2017 w51
53  2017 w52

我认为您可以使用它来代替您的查询(我当然无法对您的查询进行任何测试)

其他(希望最后)版本:

SELECT Y.CURR_WEEK,
            COALESCE(SUM(qh.totalExcl), 0) AS total
        FROM 
        (SELECT DISTINCT DATE_FORMAT(RN, '%Y-%u') AS CURR_WEEK
                     FROM 
                      (SELECT @RN:=DATE_ADD(str_to_date(  CONCAT(YEAR(UTC_TIMESTAMP()) ,'0101'), '%Y%m%d'), INTERVAL -1 DAY) AS RN
                       UNION ALL 
                       SELECT @RN:=DATE_ADD(@RN, INTERVAL 1 DAY) AS RN 
                       FROM XX1
                       CROSS JOIN XX1 X2
                       CROSS JOIN XX1 X3
                       CROSS JOIN XX1 X4
                       ) X
                       WHERE YEAR(RN)=YEAR(UTC_TIMESTAMP())
                       ) Y
        LEFT JOIN (SELECT q.date_add, q.totalExcl, h.idEmployee 
                    FROM expoled.ps_oxoquotation_quotation q 
                    INNER JOIN expoled.ps_oxoquotation_quotationstate_history h ON h.idQuotation = q.idQuotation
                    WHERE h.idEmployee = 39 AND h.idQuotationState = 3) qh ON DATE_FORMAT(qh.date_add, '%Y-%u')=Y.CURR_WEEK 
        /* are these useless? */
        LEFT JOIN expoled.ps_employee e ON qh.idEmployee = e.id_employee
        LEFT JOIN expoled.ps_sv_employee_meta m ON qh.idEmployee = m.id_employee
        GROUP BY Y.CURR_WEEK

答案 1 :(得分:1)

在MariaDB中,建立一个几周的表格非常容易:

mysql> SELECT ('2017-01-02' + INTERVAL seq WEEK) AS wk FROM seq_0_to_53;
+------------+
| wk         |
+------------+
| 2017-01-02 |
| 2017-01-09 |
| 2017-01-16 |
| 2017-01-23 |
| 2017-01-30 |
| 2017-02-06 |
| 2017-02-13 |
| 2017-02-20 |
...

基于此,你可以:

  • JOIN到您的桌子并根据需要使用wk
  • 将开始日期更改为与星期日而不是星期一(或其他)
  • 对齐
  • 选择任意多周
  • 使用WHERE wk BETWEEN ...
  • 限制事后的范围
  • 通过提取CONCAT('2017 WEEK ', seq) AS iso之类的内容,您可以获得所请求的语法。