Question

我希望在名为 week_year 的表格中使用以下架构：

Week_year = {id, week, year}

要插入每年的周数，以便2001年有第1周，第2周，第3周，......，第52周，然后从2002年开始直到2009年。

我尝试过不同的PHP脚本，但似乎无法正确使用它。我尝试了不同的表，一年一年，一周一周，然后给每周一年_id，但这似乎没有效果。

我希望有人可以帮助我创建，我相信是一个简单的PHP循环来生成这些数字并将它们插入我的MySQL数据库。

添加了作为答案发布的其他信息

我尝试过这段代码，这是一年中无休止的循环：

<?php

$year = 2001;
$week_start = 1;
$week_end = 52;

for ( $week_start = 1; $week_start <= 52; $week_start++ ) {

echo $week_start;
echo "<br />";
    for ($week_start = 1; $week_start <= 52; $year++) {
        echo $year;
        echo "<br />";
    }
}
?>

Answer 1

在SQL中执行此操作，而不是PHP：

create table artificial_range( int id not null auto_increment, ci int);

insert into artificial_range(c1) values (1);

- 现在加上artificial_range的大小

insert into artificial_range(c1) select c1 from artificial_range;

- 重复上述插入五次; - 你现在在artificial_range

中有64行

-- now insert into week_year:
insert into week_year(week, year)
select a.id, b.id + 2000
from 
  artificial_range a,
  artificial_range b 
where a.id < 53 and b.id < 10;


-- or even better, just make week_year a view:
create view week_year as
select a.id as week, b.id + 2000 as year
from 
  artificial_range a,
  artificial_range b 
where a.id < 53 and b.id < 10;

有一点需要注意：根据“周”的含义，有些年份有53周。

Answer 2

$id_start = 1;
for ($year=2002; $year<=2009; $year++) {
   $values = array();
   for ($week=1; $week<=52; $week++) {
      $values[] = implode(',', array($id_start++, $week, $year));
   }
   $query = 'INSERT INTO `week_year` (id, week, year) ' 
          . 'VALUES (' . implode('),(', $values) . ')';

   $db->query($query);
}

** 注意 **查看localtime() PHP函数。您不需要有一个包含周/年的表，只需要一个时间戳，并使用该时间戳与$info = localtime($row->timestamp, true)并使用$weekNumber = floor($info['tm_yday'] / 7);来获取您的周数。只是一个想法。

Answer 3

从php脚本中调用populate_year_week（2001,2009）存储过程！

drop table if exists year_week;

create table year_week
(
year_id smallint unsigned not null,
week_id tinyint unsigned not null,
primary key (year_id, week_id)
);

delimiter ;

drop procedure if exists populate_year_week;

delimiter #

create procedure populate_year_week
(
in from_yr smallint unsigned,
in to_yr smallint unsigned
)
proc_main:begin

declare yr smallint unsigned default 0;
declare wk tinyint unsigned default 0;

  truncate table year_week;

  -- put some validation here !
  if to_yr < from_yr then
        leave proc_main;
    end if;

  -- create years and weeks...
  set yr = from_yr;
    while yr <= to_yr do

    set wk = 1;
    while wk < 53 do
      insert into year_week (year_id, week_id) values (yr,wk);    
      set wk=wk+1;
    end while;

    set yr=yr+1;
  end while;

end proc_main #

delimiter ;

call populate_year_week(2001,2009);

select * from year_week order by year_id, week_id;

在MySQL中插入每周52周（PHP脚本）

3 个答案: