需要对列表进行排序
students = [['Prashant',32],['Pallavi',36],['Dheeraj',39],['pawan',36],
['Shivam',40],['amir',36]]
我需要按字母排序的第二个最低分数的学生名单： 恩。拳头最小= 32 = prashant 所以第二分钟= 36 我需要那个得分为36的学生名单，按字母顺序排序：
output: Amir
Pallavi
Pawan
答案 0 :(得分：1)
假设：
>>> students
[['Prashant', 32], ['Pallavi', 36], ['Dheeraj', 39], ['Pawan', 36], ['Shivam', 40], ['Amir', 36]]
怎么样：
>>> sorted(st3 for st3 in students if
... st3[1]==min(st2[1] for st2 in students if st2[1]!=min(st[1] for st in students)))
[['Amir', 36], ['Pallavi', 36], ['Pawan', 36]]
答案 1 :(得分：1)
使用students = [['Prashant',32],['Pallavi',36],['Dheeraj',39],['pawan',36],
['Shivam',40],['amir',36]]
import heapq
获得两个最小的分数然后取两者中的较大分数是非常有用的：
by_scores = {}
for n,s in students:
by_scores.setdefault(s, []).append(n)
second_lowest_score = max(heapq.nsmallest(2, by_scores.keys()))
for name in sorted(by_scores[second_lowest_score]):
print name
为避免过滤列表，请按照其分数对所有名称进行分组：
{
"gameQuestion": [
"English League Championship: What will be the match result?",
"2017 Boston Marathon: Which COUNTRY will the MEN'S WINNER represent?",
"MLB: Who will WIN this matchup?",
"English League Championship (Huddersfield Town @ Derby County): Will Derby SCORE in the 2nd Half?",
"English Premier League: What will be the match result?",
"MLB: Who will WIN this matchup?",
"NBA Eastern Conference Playoffs - 1st Rd (Cavaliers lead 1-0): Who will WIN this matchup?",
"NBA (IND@CLE): Which PLAYER will SCORE a HIGHER PERCENTAGE of their TEAM'S TOTAL POINTS in the 1st Half?",
"NHL Eastern Conference Playoffs - 1st Rd (Series tied 1-1): Who will WIN this matchup?",
"NHL Eastern Conference Playoffs - 1st Rd (Series tied 1-1): Who will WIN this matchup?",
"MLB: Who will WIN this matchup?",
"MLB: Who will WIN this matchup?",
"MLB: Who will WIN this matchup?",
"MLB: Who will WIN this matchup?",
"NBA (IND@CLE): Will a 3-POINTER be MADE in the FIRST 2 MINUTES of the 3rd Quarter?",
"NBA Western Conference Playoffs - 1st Rd (Spurs lead 1-0): What will be the GAME RESULT?",
"NHL Western Conference Playoffs - 1st Rd (Predators lead 2-0): Who will WIN this matchup?",
"NHL Western Conference Playoffs - 1st Rd (Ducks lead 2-0): Who will WIN this matchup?",
"MLB: Who will WIN this matchup?",
"MLB: Who will WIN this matchup?"
],
"propVal": [
"m57338o58525",
"m57338o58526",
"m57336o58521",
"m57336o58522",
"m57329o4111",
"m57329o12",
"m57316o793",
"m57316o726",
"m57319o58515",
"m57319o58516",
"m57322o423",
"m57322o461",
"m57323o517",
"m57323o515",
"m57327o206",
"m57327o15",
"m57330o14",
"m57330o35",
"m57331o21",
"m57331o148",
"m57298o27453",
"m57298o112",
"m57320o58517",
"m57320o58518",
"m57318o58513",
"m57318o58514",
"m57325o481",
"m57325o479",
"m57326o463",
"m57326o5964",
"m57333o19384",
"m57333o78",
"m57334o3",
"m57334o5"
],
"info": [
"Opponents",
" Aston Villa: Win or Draw",
"@ Fulham: Win",
"Kenya",
" Any Other Country",
" Tampa Bay Rays (6-7) Snell",
" @ Boston Red Sox (7-5) Wright",
" Yes: Derby Scores 1+ Goals in 2nd Half",
" No: No Derby Goal in 2nd Half",
" Arsenal: Win",
" @ Middlesbrough: Win or Draw",
" Chicago White Sox (6-5) Holland",
" @ New York Yankees (8-4) Montgomery",
" Indiana Pacers (42-40)",
" @ Cleveland Cavaliers (51-31)",
" Paul George (IND)",
" LeBron James (CLE) or Tie",
" Ottawa Senators (44-28-10)",
" @ Boston Bruins (44-31-7)",
" Washington Capitals (55-19-8)",
" @ Toronto Maple Leafs (40-27-15)",
" Pittsburgh Pirates (6-6) Nova",
" @ St. Louis Cardinals (3-9) Lynn",
" Milwaukee Brewers (7-6) Anderson",
" @ Chicago Cubs (6-6) Lackey",
" Cleveland Indians (5-7) Salazar",
" @ Minnesota Twins (7-5) Gibson",
" Los Angeles Angels (6-7) Chavez",
" @ Houston Astros (8-4) Morton",
" Yes: 3PM in First 2 Min of 3rd Qtr",
" No: No 3PM in First 2 Min of 3rd Qtr",
" Grizzlies: Win or Single Digit Loss",
" @ Spurs: Win By Double Digits",
" Chicago Blackhawks (50-23-9)",
" @ Nashville Predators (41-29-12)",
" Anaheim Ducks (46-23-13)",
" @ Calgary Flames (45-33-4)",
" Miami Marlins (7-5) Koehler",
" @ Seattle Mariners (5-8) Miranda",
" Arizona Diamondbacks (8-5) Ray",
" @ Los Angeles Dodgers (7-6) McCarthy"
]
答案 2 :(得分：0)
排序时可以使用多个键：
>>> import operator
>>> students = [['Prashant',32],['Pallavi',36],['Dheeraj',39],['Pawan',36],['Shivam',40],['Amir',36]]
>>> sorted_students = sorted(students, key=operator.itemgetter(1, 0))
>>> sorted_students
[['Prashant', 32], ['Amir', 36], ['Pallavi', 36], ['Pawan', 36], ['Dheeraj', 39], ['Shivam', 40]]
答案 3 :(得分：0)
这一个：
students = [['Prashant',32],['Pallavi',36],['Dheeraj',39],['Pawan',36],['Shivam',40],['Amir',36]]
names = []
s = set(i[1] for i in students)
sec_min = sorted(s)[1]
for j in students:
if (j[1] == sec_min):
names.append (j[0])
names.sort()
print names
答案 4 :(得分：0)
students = [['Prashant',32],['Pallavi',36],['Dheeraj',39],['pawan',36],['Shivam',40],['amir',36]]
stud = dict()
'''
Save students list into a dictionay with score as dictionary index
i.e {32: 'Prashant', 36: 'Pallavi','pawan','amir'
'''
for student in students:
if student[1] in stud:
stud[student[1]].append(student[0])
else:
stud[student[1]]=[]
stud[student[1]].append(student[0])
sorted_names=sorted(list(map(str.title,stud[sorted(stud.keys())[1]])))
for student in sorted_names:
print(student)
'''
BREAKDOWN
scores = sorted(stud.keys())
second_score = scores[1]
second_score_students = stud[second_score]
second_score_students = list(map(str.title,second_score_students))
sorted_names=sorted(second_score_students)
'''