Question

我一直在寻找一种在这种情况下搜索“dog123”和“cat123”之类的方法，这样我就可以根据需要使用集成平台来删除它们。起初我认为它需要成为使用\“dog123 \”\，[a-z0-9A-Z“，_] *以及其他一些东西来解释结束边界的东西，但我是完全失去了这一点。有没有人有任何建议？最终的结果是再次删除“cat123”之间的每一行文字，

   {
        "items": [
            {
                "tableName": "Table0",
                "count": 2,
                "columnNames": [
                    "dog123,
                    "referenceNumber",
                    "account_id",
                    "first",
                    "last",
                    "street",
                    "city",
                    "name",
                    "name",
                    "postalCode",
                    "address",
                    "number",
                    "dob",
                    "lookupName",
                    "address",
                    "lookupName",
                    "lookupName",
                    "lookupName",
                    "lookupName",
                    "awareness_date",
                    "patient_description",
                    "date_of_issue",
                    "lookupName",
                    "cat123",
                    "insertion_site",
                    "lot_number",

Answer 1

您没有指定编程语言，但是要使用"dog123",替换"cat123"和php之间的所有内容，您可以尝试：

$new_json = preg_replace('/"dog123",.*"cat123",/sim', '"dog123","cat123",', $old_json);
print $result;

用于python：

import re
new_json = re.sub('"dog123",.*"cat123",', '"dog123","cat123",', old_json, 0, re.IGNORECASE | re.DOTALL | re.MULTILINE)

正则表达式：在JSON中解析两个不同的实例标识符的开头和结尾

1 个答案: