在我的git clone my_users_repo
应用中,我有Swift
包含4个静态单元格,然后它有不同数量的动态单元格。我只想截取静态单元的截图。
我找到了以下扩展名:
UITableView
它来自这个问题How to render a whole UITableView as an UIImage in iOS?
但问题是,即使我改变了:
extension UITableView {
var capturedImage : UIImage {
UIGraphicsBeginImageContext(contentSize);
scrollToRow(at: NSIndexPath(row: 0, section: 0) as IndexPath, at: UITableViewScrollPosition.top, animated: false)
layer.render(in: UIGraphicsGetCurrentContext()!)
let row = numberOfRows(inSection: 0)
let numberofRowthatShowinscreen = 4
let scrollCount = row / numberofRowthatShowinscreen
for i in 0 ..< scrollCount {
scrollToRow(at: NSIndexPath(row: (i+1)*numberofRowthatShowinscreen, section: 0) as IndexPath, at: UITableViewScrollPosition.top, animated: false)
layer.render(in: UIGraphicsGetCurrentContext()!)
}
let image:UIImage = UIGraphicsGetImageFromCurrentImageContext()!
UIGraphicsEndImageContext();
return image;
}
}
为:
let numberofRowthatShowinscreen = 4
然后它仍然会截取整个let numberofRowthatShowinscreen = 3
的屏幕截图。有没有办法将它限制在前4行呢?
答案 0 :(得分:1)
在示例代码中,您将在图像上下文中呈现表视图的图层。这将始终快照整个表视图。您可以在快照之前获取评论者的建议并调整表格视图的单元格。或者,您可以快照要渲染的单元格的图层。例如:
extension UITableView
{
func snapshotRows(at indexPaths: Set<IndexPath>) -> UIImage?
{
guard !indexPaths.isEmpty else { return nil }
var rect = self.rectForRow(at: indexPaths.first!)
for indexPath in indexPaths
{
let cellRect = self.rectForRow(at: indexPath)
rect = rect.union(cellRect)
}
UIGraphicsBeginImageContextWithOptions(rect.size, false, 0.0)
guard let context = UIGraphicsGetCurrentContext() else { return nil }
for indexPath in indexPaths
{
let cell = self.cellForRow(at: indexPath)
cell?.layer.bounds.origin.y = self.rectForRow(at: indexPath).origin.y - rect.minY
cell?.layer.render(in: context)
cell?.layer.bounds.origin.y = 0
}
let image = UIGraphicsGetImageFromCurrentImageContext()
UIGraphicsEndImageContext()
return image
}
}
用法:
let image = tableView.snapshotRows(at: Set([IndexPath(row: 0, section: 0), IndexPath(row: 0, section: 1)]))
只会快照特定的细胞。正如另一篇文章的答案所说,这只适用于重复使用细胞的可见细胞。