Question

我在以下结构中有两个表：

sales
 |date       |time     | name   | total |
 |2017-04-01 |10:23:59 | aaa    |  100  |
 |2017-04-01 |10:23:59 | aaa    |  150  |
 |2017-04-01 |11:33:30 | bbb    |  200  |
 |2017-04-01 |11:33:30 | bbb    |  120  |
 |2017-04-02 |10:50:59 | aaa    |  70   |
 |2017-04-02 |10:30:59 | bbb    |  35   |

payment
 |date       |time     | name   | amount |
 |2017-04-01 |10:23:59 | aaa    |  300   |
 |2017-04-01 |11:33:30 | bbb    |  400   |
 |2017-04-02 |10:50:59 | aaa    |  425   |
 |2017-04-02 |10:30:59 | bbb    |  600   |

条款

sales.time = payment.time
where date = 2017-04-01
sum（sales.total）和sum（payment.amount）
按时间分组

我想要这个结果

 |date       |time     | name   | sum(total) | sum(amount)|
 |2017-04-01 |13:23:59 | aaa    |    250     |    300     |
 |2017-04-01 |12:33:30 | bbb    |    320     |    400     |

表格结构

CREATE TABLE `payment` (`id` int(5) NOT NULL,`date` date NOT NULL,`time` time NOT NULL,`name` varchar(10) NOT NULL,`amount` varchar(10) NOT NULL) ENGINE=InnoDB DEFAULT CHARSET=latin1 ROW_FORMAT=COMPACT;
INSERT INTO `payment` (`id`, `date`, `time`, `name`, `amount`) VALUES(3, '2017-04-01', '10:23:59', 'aaa', '300'),(4, '2017-04-01', '11:33:30', 'bbb', '400'),(5, '2017-04-02', '10:50:59', 'aaa', '425'),(6, '2017-04-02', '10:30:59', 'bbb', '600');
CREATE TABLE `sales` ( `id` int(5) NOT NULL,`date` date NOT NULL,`time` time NOT NULL,`name` varchar(10) NOT NULL,`total` int(10) NOT NULL) ENGINE=InnoDB DEFAULT CHARSET=latin1;
INSERT INTO `sales` (`id`, `date`, `time`, `name`, `total`) VALUES(1, '2017-04-01', '10:23:59', 'aaa', 100),(2, '2017-04-01', '10:23:59', 'aaa', 150),(3, '2017-04-01', '11:33:30', 'bbb', 200),(4, '2017-04-01', '11:33:30', 'bbb', 120),(5, '2017-04-02', '10:50:59', 'aaa', 70),(6, '2017-04-02', '10:50:59', 'bbb', 35);
ALTER TABLE `payment` ADD PRIMARY KEY (`id`);
ALTER TABLE `sales` ADD PRIMARY KEY (`id`);
ALTER TABLE `payment` MODIFY `id` int(5) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=7;
ALTER TABLE `sales` MODIFY `id` int(5) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=7;

查询

SELECT sales.time,sales.name,  
SUM(sales.total),SUM(payment.amount)
FROM sales,payment  
WHERE sales.time=payment.time
and sales.date like '2017-04-01%'
GROUP BY sales.time
ORDER BY sales.time;

结果是

10:23:59    aaa 250 600
11:33:30    bbb 320 800

Answer 1

您将付款金额与销售记录数相乘，因为您在汇总金额之前加入了包含所有销售记录的所有付款记录。

首先聚合，然后才加入。

如果每个日期，时间和名称始终只能有一个付款记录：

select p.name, p.time, p.name, s.sales_total, p.amount
from payments p
join
(
  select date, time, name, sum(total) as total
  from sales
  group by date, time, name
) s
 on s.date = p.date and s.time = p.time and s.name = p.name
where p.date = date '2017-04-01';

否则：

select p.name, p.time, p.name, s.total, p.amount
(
  select date, time, name, sum(amount) as amount
  from payments
  group by date, time, name
) p
join
(
  select date, time, name, sum(total) as total
  from sales
  group by date, time, name
) s
 on s.date = p.date and s.time = p.time and s.name = p.name
where p.date = date '2017-04-01';

Mysql连接两个表总和，where和group by

1 个答案: