Question

我有两张桌子

表1：

    ref       status

    abc     1
    abc     1
    abc     2
    abc     3
    abc     5(not in Table2)
    abc     5(not in Table2)

表2：

    ref          status

    abc     1
    abc     1
    abc     2
    abc     3
    abc             4(not in Table1)
    abc     4(not in Table1)

我想加入这两个表并执行分组，以便最终结果如下所示：

结果表：参考状态

    abc     1
    abc     2
    abc     3
    abc     4
    abc     5

我试过这个

    SELECT DISTINCT Table1.ref, Table1.status, Table2.ref, Table2.status
    FROM Table1, Table2
    GROUP BY Table1.ref, Table1.status, Table2.ref, Table2.status;

Answer 1

SELECT DISTINCT ref, status
FROM
(
    SELECT ref, status
    FROM Table1
    UNION ALL
    SELECT ref, status
    FROM Table2
) x

SQL Fiddle example

Answer 2

请尝试以下代码：

SELECT DISTINCT ref, status
FROM Table1
UNION 
SELECT DISTINCT ref, status
FROM Table2

通过xyz加入两个表和组

2 个答案: