Question

我正在开发一个包含按钮的JFrame /面板。当用户单击该按钮时，我想要一个图像（预先存储在计算机硬盘中）在前面的屏幕上打开。

button.addActionListener(new ActionListener(){
        public void actionPerformed(ActionEvent e){
        //here i want a code that will somehow open the image from a given directory
            }});

有关如何解决这个问题的任何建议？我必须告诉图像的存储位置并触发虚拟“双击”，以便在前面的屏幕上弹出图像。甚至可以使用java来同步这样的计算机功能吗？

Answer 1

我不知道一个非常短的方式，但我会使用这样的东西（因为qick hack得到一个印象）：

  try {
    // this is a new frame, where the picture should be shown
    final JFrame showPictureFrame = new JFrame("Title");
    // we will put the picture into this label
    JLabel pictureLabel = new JLabel();

    /* The following will read the image */
    // you should get your picture-path in another way. e.g. with a JFileChooser
    String path = "C:\\Users\\Public\\Pictures\\Sample Pictures\\Koala.jpg";
    URL url = new File(path).toURI().toURL();
    BufferedImage img = ImageIO.read(url);
    /* until here */

    // add the image as ImageIcon to the label
    pictureLabel.setIcon(new ImageIcon(img));
    // add the label to the frame
    showPictureFrame.add(pictureLabel);
    // pack everything (does many stuff. e.g. resizes the frame to fit the image)
    showPictureFrame.pack();

    //this is how you should open a new Frame or Dialog, but only using showPictureFrame.setVisible(true); would also work.
    java.awt.EventQueue.invokeLater(new Runnable() {

      public void run() {
        showPictureFrame.setVisible(true);
      }
    });

  } catch (IOException ex) {
    System.err.println("Some IOException accured (did you set the right path?): ");
    System.err.println(ex.getMessage());
  }

Answer 2

我认为这会奏效......

代码：

process = new ProcessBuilder（“mspaint”，“yourFileName.jpeg”）。start（）;

这将使用mspaint打开您的图像文件.....

并使用 * Java高级成像（JAI） *

Answer 3

试试此代码

 try
{
  // the line that reads the image file
  BufferedImage image;


  // work with the image here ...
        image = ImageIO.read(new File("C://Users//Neo//Desktop//arduino.jpg"));


        jLabel1.setIcon(new ImageIcon(image));
} 
catch (IOException e)
{
  // log the exception
  // re-throw if desired
}

Answer 4

我不确定但是试试这个......

try
{

    JLabel picture=new JLabel();

    ImageIcon ic=new ImageIcon(Toolkit.getDefaultToolkit().getImage(getClass().getResource("C:\\Users\\Desktop\\xyz.jpg")));

    picture.setIcon(ic);

}
catch(Exception)
{
}

如何使用Java打开.bmp / .jpeg图像

4 个答案: