Question

str_replace中的while函数仅返回第一行信息。这是电子邮件模板。

// I have a macro in my message. (member name)
$message = "Hi {%write_member_name%} how are you?";

$connect = mysql_query("SELECT * FROM members"); 
while($row=mysql_fetch_array($connect)){


$membername = $row["member_name"];

$message = str_replace('{%write_member_name%}', $membername ,$message);

echo $message."<br/>";

}

我应该得到的结果。

嗨杰克你好吗？

你好 Mike 你好吗？

你好 Alex 你好吗？

但是我得到了错误的结果：

嗨杰克你好吗？

如果我不使用str_replace函数，它可以正常工作。

如何在while循环中使用str_replace函数？谢谢。

Answer 1

您使用sprintf()作为此

用作为参数传递的变量替换百分号（％）：

$membername = "";
$connect = mysql_query("SELECT * FROM members");
while ($row = mysql_fetch_array($connect)) {
    $membername = $row["member_name"];
    $message = sprintf("Hi %s how are you?", $membername); // pass argument here
    echo $message . "<br/>";
    $membername = "";
}

在PHP 7.0.0中正式弃用并删除了
mysql_ *函数。您应该用PDO或MySQLi更新您的代码。

Answer 2

    $connect = mysql_query("SELECT * FROM members"); 
    while($row=mysql_fetch_assoc($connect)){
        $message = "Hi {%write_member_name%} how are you?";
        $membername = $row["member_name"];

        $message = str_replace('{%write_member_name%}', $membername ,$message);

        echo $message."<br/>";

    }

Answer 3

更容易：

$connect = mysql_query("SELECT * FROM members"); 
while($icerik=mysql_fetch_array($connect)){

echo $message =  "Hi" . $row["member_name"] . "how are you? <br/>";


}

PHP循环中的str_replace

3 个答案: