Question

<?php 

$url = "http://localhost/news&lang=en&lang=sk&lang=sk&lang=sk&lang=en";

$langs = array ('sk', 'en');

foreach ($langs as $lang) {
    $search = '&lang='.$lang;    
    $new = str_replace($search, "", $url);
}

echo $new; // output: http://localhost/news

?>

问：如何从字符串中删除所有参数（＆amp; lang = en，＆amp; lang = sk）？

提前谢谢

Answer 1

您正在做的是每次都创建一个新变量$new，这样就不会对$url做任何好事。尝试将str_replace分配回其原始变量，如：

$url = "http://localhost/news&lang=en&lang=sk&lang=sk&lang=sk&lang=en";

$langs = array ('sk', 'en');

foreach ($langs as $lang) {
    $search = '&lang='.$lang;    
    $url = str_replace($search, "", $url);
}

echo $url; // output: http://localhost/news

Answer 2

替代方案：

首先：

$url = "http://localhost/news&lang=en&lang=sk&lang=sk&lang=sk&lang=en";
echo preg_replace("#&lang=(en|sk)#", "", $url);

第二

$url = "http://localhost/news&lang=en&lang=sk&lang=sk&lang=sk&lang=en";
echo str_replace(array("&lang=en", "&lang=sk"), "", $url);

更新：适用于$ lang的长数组：

$url = "http://localhost/news&lang=en&lang=sk&lang=sk&lang=sk&lang=en";
echo preg_replace("#&lang=(".implode("|", $lang).")#", "", $url);

Answer 3

您想使用parse_url（）http://www.php.net/manual/en/function.parse-url.php然后使用http_build_query（）http://php.net/manual/en/function.http-build-query.php

foreach循环中的str_replace

3 个答案: