如何在RxJS Observable满足条件之前重复ajax请求?

时间:2017-04-13 19:48:18

标签: javascript rxjs rxjs5 reactivex

我尝试重复请求,直到响应有使用RxJS的数据,此时我想调用成功(或失败)处理程序,但我遇到了麻烦w / RxJS。这是我目前的做法:

// ... redux-observable action observable
.mergeMap(() =>
    fetchData()
    .repeatWhen(response =>
        response.takeWhile(({ data }) => !data.length)
        .of(response)
    )
)
.map(successFunction)
.catch(failureFunction);

免责声明:我对RxJS很新......

3 个答案:

答案 0 :(得分:4)

听起来你想要抑制ajax结果并重试,直到你得到你想要的响应。我是这样做的:

// observable that will re-fetch each time it is subscribed
const request = Observable.defer(() => fetchData());

// each time request produces its value, check the value
// and if it is not what you want, return the request
// observable, else return an observable with the response
// use switchMap() to then subscribe to the returned
// observable.
const requestWithRetry = request.switchMap(r =>
    r.data.length ? Observable.of(r) : requestWithRetry);

答案 1 :(得分:3)

空数据不是错误,所以首先我们检查数据是否为空,如果是,则抛出错误。 然后retryWhen可用于测试此错误,并在其发生时重试。

.mergeMap(() =>
   fetchData()
   .map(data => {
       if (!data.length) {
          throw 'no data';
       } 
       return data;
    })
   .retryWhen(errors => errors.takeWhile(error => error === 'no data'))
)
.map(successFunction)
.catch(failureFunction);

答案 2 :(得分:3)

在一个间隔上重复请求,过滤其结果并采取一次发射更简单。

Observable.timer(0, 500)
  .flatMap(() => fetchData())
  .filter(r => r.data && r.data.length)
  .take(1)
  .timeout(10000)

http://jsbin.com/cafericore/1/edit?js,console