Question

我有一个这样的数组：

a=[["Wed", 27], ["Sun", 90], ["Fri", 69], ["Tue", 47], ["Mon", 54], ["Thu", 40], ["Sat", 78]];

我想通过python 2.7将数组排序为星期几。像这样;

[["Mon", 54], ["Tue", 47], ["Wed", 27], ["Thu", 40], ["Fri", 69], ["Sat", 78], ["Sun", 90]]

...谢谢

Answer 1

您可以创建一个映射，然后按此排序。

import operator as op

mapping = {'Mon':0,'Tue':1,'Wed':2,'Thu':3,'Fri':4,'Sat':5,'Sun':6}
orig_list = [["Wed", 27], ["Sun", 90], ["Fri", 69], ["Tue", 47], 
             ["Mon", 54], ["Thu", 40], ["Sat", 78]]
new_list = zip(orig_list,[mapping[i[0]] for i in orig_list])
new_list.sort(key=op.itemgetter(1))

收率：

>>> new_list
[(['Mon', 54], 0), (['Tue', 47], 1), (['Wed', 27], 2), (['Thu', 40], 3), 
 (['Fri', 69], 4), (['Sat', 78], 5), (['Sun', 90], 6)]

Answer 2

您可以创建一个按工作日排序的列表，然后按其键对列表a进行排序：

>>> a = [["Wed", 27], ["Sun", 90], ["Fri", 69], ["Tue", 47], ["Mon", 54], ["Thu", 40], ["Sat", 78]]
>>> order = ["Mon", "Tue", "Wed", "Thu", "Fri", "Sat", "Sun"]
>>> sorted(a, key=lambda x: order.index(x[0]))

输出将是：

[[＆＃39; Mon＆＃39;，54]，[＆＃39; Tue＆＃39;，47]，[＆＃39;周三＆＃39;，27]，[＆＃39;周四＆＃ 39;，40]，[＆＃39; Fri＆＃39;，69]，[＆＃39; Sat＆＃39;，78]，[＆＃39; Sun＆＃39;，90]]

Answer 3

您可以在值和数字之间定义映射，而无需使用任何导入。

a = [["Wed", 27], ["Sun", 90], ["Fri", 69], ["Tue", 47], ["Mon", 54], ["Thu", 40], ["Sat", 78]]

mapping = {
  "Mon": 1,
  "Tue": 2,
  "Wed": 3,
  "Thu": 4,
  "Fri": 5,
  "Sat": 6,
  "Sun": 7
}

a.sort(key = lambda x: mapping[x[0]])

print(a)

在此指定您要使用匿名函数对列表进行排序。此匿名函数将提取字符串（例如“Sun”）并获取映射中对应的数字。

Python将多维数组排序为星期几

3 个答案: