Question

我有一个名为file_1.py

的python文件

it has some code in which, i just have to change a word "file_1" to "file_2"

并保留其他函数的缩进

and save it as file_2.py

单词file_1

有3次出现

i have to do this for 100 such times. `file_1.py, file_2.py.....file_100.py`

有什么方法可以实现自动化吗？

Answer 1

运行此脚本：

import fileinput

with fileinput.FileInput('file_1.py', inplace=True, backup='.bak') as file:
    for line in file:
        print(line.replace('file_1', 'file_2'), end='')

希望这有帮助：）

Answer 2

创建一个脚本：

首先：读取文件

new_content = content.replace("file1","file2")

第二名：替换文件名

with open("./file2.py", "w") as f:
    f.write(new_content)

第三：写新文件（我建议你写一个新文件）

filenames = ["file" + str(item) for item in range(1,100)]
for filename in filenames:
    with open(filename + ".py") as f:
        content = f.read()
    new_filename = filename[:-1] + str(int(filename[-1]) + 1)
    new_content = content.replace(filename,new_filename)
    with open("./another_folder" + new_filename + ".py", "w") as f:
        f.write(new_content)

如果您有多个文件，请使用

之类的内容

String link = "https://stackoverflow.com/questions/ask ";
if (link.split("/").length >= 3 ) {
    System.out.println("CORRECT");
}else{
    System.out.println("NOT CORRECT");
}

自动更改python文件并使用不同的文件名保存

2 个答案: