我需要一个正则表达式来获取所有后续字符串的 src 值,考虑单引号,双引号和无引号。
使用双引号:
var a = '<script class="anyClass" src="anyFile.js" id="anyID">';
var b = '<script class="anyClass" src="anyFile.js">';
var c = '<script src="anyFile.js" id="anyID">';
var d = '<script src="anyFile.js">';
使用单引号:
var e = "<script class='anyClass' src='anyFile.js' id='anyID'>";
var f = "<script class='anyClass' src='anyFile.js'>";
var g = "<script src='anyFile.js' id='anyID'>";
var h = "<script src='anyFile.js'>";
没有引言:
var i= "<script class=anyClass src=anyFile.js id=anyID>";
var j= "<script class=anyClass src=anyFile.js>";
var k= "<script src=anyFile.js id=anyID>";
var l= "<script src=anyFile.js>";
预期匹配/返回
anyFile.js
我有这个看起来很糟糕的解决方案:
var file = "";
var match = 'src="';
if(a.indexOf(match)>=0){
file = a.split(match);
file = file[1];
file = file.split('.js"');
file = file[0] + ".js";
}
else{
match = "src='";
if(a.indexOf(match)>=0){
file = a.split(match);
file = file[1];
file = file.split(".js'");
file = file[0] + ".js";
}
else{
match = "src=";
if(a.indexOf(match)>=0){
file = a.split(match);
file = file[1];
file = file.split('.js');
file = file[0] + ".js";
}
else {
file = "no match";
}
}
}
但它可以匹配错误的src
属性,所以我需要一个正则表达式。
非常感谢任何帮助。
解决方案(特别感谢Rajesh)
var a = "<script class='anyClass' src='anyFile.js' id='anyID'>";
var b = '<script class="anyClass" src="anyFile.js">';
var c = '<script src="anyFile.js" id="anyID">';
var d = '<script src="anyFile.js">';
var e = "<script class='anyClass' src='anyFile.js' id='anyID'>";
var f = "<script class='anyClass' src='anyFile.js'>";
var g = "<script src='anyFile.js' id='anyID'>";
var h = "<script src='anyFile.js'>";
var i= "<script class=anyClass src=anyFile.js id=anyID>";
var j= "<script class=anyClass src=anyFile.js>";
var k= "<script src=anyFile.js id=anyID>";
var l= "<script src=anyFile.js>";
var l= "<script src=anyFile.js>";
function getSrc(str){
var regex = /src=["']*[^"' >]+/;
var match = str.match(regex);
if(match!==null){
match = match[0];
var replaceRegex = /src=["' ]*/;
match = match.replace(replaceRegex, "")
}
else{
match = "no match";
}
console.log(match);
}
[a,b,c,d,e,f,g,h,i,j,k,l].forEach(getSrc)
答案 0 :(得分:1)
这是我想出来实现这一目标的。欢迎任何改进:
script src=["']?(\w+\.js)
https://regex101.com/r/6NCj94/2
或者您的脚本名称类似于jquery.min.js
的情况:
script src=["']?(.*\.js)
答案 1 :(得分:1)
您可以尝试这样的事情:
<强>逻辑:强>
src=
,后跟单引号/双引号[可选],后跟任何非单/双引号。src="anyfile.js
。src=
,然后是可选引号。
var a = '<script class="anyClass" src="anyFile.js" id="anyID">';
var b = '<script class="anyClass" src="anyFile.js">';
var c = '<script src="anyFile.js" id="anyID">';
var d = '<script src="anyFile.js">';
var i= "<script class=anyClass src=anyFile.js id=anyID>";
var j= "<script class=anyClass src=anyFile.js>";
var k= "<script src=anyFile.js id=anyID>";
var l= "<script src=anyFile.js>";
function getSrc(str){
var regex = /src=["']*[^"' >]+/;
var match = str.match(regex)[0];
var replaceRegex = /src=["' ]*/;
match = match.replace(replaceRegex, "")
console.log(match)
}
[a,b,c,d,i,j,k,l].forEach(getSrc)
答案 2 :(得分:1)
我更喜欢以正确的方式使用DOM:
sub_query = Model.select(:column_name).where(condition).to_sql
Model.
select("column_name(s)").
where("column_name operator ALL (#{sub_query})")
完整的javascript代码:
var scripts = document.getElementsByTagName('script');
Array.prototype.forEach.call(scripts, (script => console.log(script.src)));
var a = '<script src="anyFile1.js"><\/script>';
var b = '<script src=\'anyFile2.js\'><\/script>';
var c = '<script src=anyFile3.js><\/script>';
var html = document.createElement('div');
html.innerHTML = a + b + c;
var scripts = html.getElementsByTagName('script');
[].forEach.call(scripts, (script => console.log(script.src)));
<script[^>]+?src=(['"]?)([^\s>]+)\1[^>]*>(<\/script>)?
完整的JS代码:
str.replace(/<script[^>]+?src=(['"]?)([^\s>]+)\1[^>]*>(<\/script>)?/g, (
(match, $0, $1) => $1 ? array.push($1) : ''
))