感谢您提前阅读并抱歉我的英语不好。
我正在使用OpenCV开发Webcam Streaming。 我的最终目标是制作类似Skype的应用程序。 所以我先尝试基本的1:1 TCP模型。
关于TCP 1:1模型,
连接后,客户端发送其实时网络摄像头帧和服务器接收并将其显示在其jpanel上。
到目前为止,我确实收到了一张照片并在jpanel上显示
我试图接收连续的帧
起初,问题是服务器端套接字似乎在等待客户端的输入完成,即它永远不会停止,因为实时帧连续发送。
所以我在发送帧之前发送了每个帧大小以逃避不可阻挡的等待
但它不能很好地运作。客户端继续发送帧,但服务器没有很好地接收它
例如,如果客户端发送大约25k字节大小的帧,则服务器每次读取只接收1到3个字节,即使缓冲区大小为512.
ClientThread.java
package client;
import java.io.ByteArrayInputStream;
import java.io.ByteArrayOutputStream;
import java.io.DataInputStream;
import java.io.DataOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.net.Socket;
import javax.imageio.ImageIO;
import video.VideoCap;
public class ClientThread extends Thread
{
String serverIp;
int serverPort;
Socket socket;
VideoCap videoCap;
public ClientThread(Socket socket, String serverIp, int serverPort, VideoCap videoCap)
{
this.socket = socket;
this.serverIp = serverIp;
this.serverPort = serverPort;
this.videoCap = videoCap;
}
public void run()
{
while (ClientUI.calling)
{
try
{
InputStream in = socket.getInputStream();
DataInputStream dis = new DataInputStream(in);
OutputStream out = socket.getOutputStream();
DataOutputStream dos = new DataOutputStream(out);
// receive
int bufSize = dis.readInt();
while (ClientUI.calling)
{
ByteArrayOutputStream baos = new ByteArrayOutputStream();
ImageIO.write(videoCap.getOneFrame(), "jpg", baos);
InputStream inputImage = new ByteArrayInputStream(baos.toByteArray());
// frame size
dos.writeInt(baos.size());
out(inputImage, baos, bufSize);
Thread.sleep(5000);
}
}
catch (IOException | InterruptedException e)
{
e.printStackTrace();
}
}
}
void out(InputStream in, OutputStream out, int bufSize)
{
long size = 0;
try
{
byte[] buf = new byte[bufSize];
int n;
while ((n = in.read(buf)) > 0)
{
out.write(buf, 0, n);
size += n;
System.out.println("size: " + size);
}
}
catch (IOException e)
{
e.printStackTrace();
}
finally
{
System.out.println(getClass().getName() + " :: out >>> sent size: " + size);
}
}
}
ServerThread.java
package server;
import java.awt.image.BufferedImage;
import java.io.ByteArrayInputStream;
import java.io.ByteArrayOutputStream;
import java.io.DataInputStream;
import java.io.DataOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.net.ServerSocket;
import java.net.Socket;
import javax.imageio.ImageIO;
import javax.swing.JPanel;
public class ServerThread extends Thread
{
ServerSocket serverSocket;
Socket socket;
JPanel panel;
byte[] buf;
public ServerThread(ServerSocket serverSocket, JPanel panel, int bufSize)
{
this.serverSocket = serverSocket;
this.panel = panel;
buf = new byte[bufSize];
}
public void run()
{
try
{
System.out.println("waiting for client");
socket = serverSocket.accept();
System.out.println("client accepted");
InputStream in = socket.getInputStream();
DataInputStream dis = new DataInputStream(in);
OutputStream out = socket.getOutputStream();
DataOutputStream dos = new DataOutputStream(out);
dos.writeInt(buf.length);
while (ServerUI.calling)
{
int frameSize = dis.readInt();
ByteArrayOutputStream outImage = new ByteArrayOutputStream();
long size = 0;
int n;
while (frameSize >= size)
{
n = dis.read(buf);
if (n == -1)
break;
outImage.write(buf, 0, n);
size += n;
System.out.println(n);
}
InputStream inputImage = new ByteArrayInputStream(outImage.toByteArray());
BufferedImage bufferedImage = ImageIO.read(inputImage);
panel.getGraphics().drawImage(bufferedImage, 0, 0, null);
}
}
catch (IOException e)
{
e.printStackTrace();
}
}
}
答案 0 :(得分:0)
我将DataOutput / InputStream更改为ObjectOutput / InputStream。 我不确定为什么它不顺利,但我想这是因为序列化问题。但字节不需要序列化,所以我不确切知道。
无论如何我都会提供工作代码。由于AudioServer我分为两个线程,所以以前的代码和下面的代码是完全不同的。
VideoServerThread.java
import java.awt.image.BufferedImage;
import java.io.ByteArrayInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.ObjectInputStream;
import java.io.Serializable;
import java.net.ServerSocket;
import java.net.Socket;
import javax.imageio.ImageIO;
import javax.swing.JPanel;
public class VideoServerThread extends Thread
{
private ServerSocket serverSocket;
int videoServerPort;
private Socket socket;
private JPanel panel;
private boolean calling;
public VideoServerThread(ServerSocket serverSocket, int videoServerPort, JPanel panel, boolean calling)
{
this.serverSocket = serverSocket;
this.videoServerPort = videoServerPort;
this.panel = panel;
this.calling = calling;
}
@Override
public void run()
{
System.out.println("Video Server opened!");
try
{
serverSocket = new ServerSocket(videoServerPort);
socket = serverSocket.accept();
InputStream in = socket.getInputStream();
ObjectInputStream ois = new ObjectInputStream(in);
BufferedImage bufferedImage;
InputStream inputImage;
Frame f;
while (calling)
{
f = (Frame) ois.readObject();
inputImage = new ByteArrayInputStream(f.bytes);
bufferedImage = ImageIO.read(inputImage);
panel.getGraphics().drawImage(bufferedImage, 0, 0, panel.getWidth(), panel.getHeight(), null);
panel.getGraphics().drawImage(bufferedImage, 0, 0, null);
bufferedImage.flush();
inputImage.close();
f = null;
}
}
catch (IOException e)
{
e.printStackTrace();
}
catch (ClassNotFoundException e)
{
e.printStackTrace();
}
}
class Frame implements Serializable
{
public byte[] bytes;
public Frame(byte[] bytes)
{
this.bytes = bytes;
}
public int size()
{
return bytes.length;
}
}
}
VideoClientThread.java
import java.awt.image.BufferedImage;
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.io.ObjectOutputStream;
import java.net.Socket;
import javax.imageio.ImageIO;
import common.Frame;
import video.VideoCap;
public class VideoClientThread extends Thread
{
private final String formatType = "jpg";
private VideoCap videoCap;
private Socket socket;
private String ip;
private int port;
private boolean calling;
public VideoClientThread(VideoCap videoCap, Socket socket, String ip, int port, boolean calling)
{
this.videoCap = videoCap;
this.socket = socket;
this.ip = ip;
this.port = port;
this.calling = calling;
}
public void run()
{
try
{
socket = new Socket(ip, port);
socket.setSoTimeout(5000);
ObjectOutputStream oos = new ObjectOutputStream(socket.getOutputStream());
Frame f;
BufferedImage bufferedImage;
while (calling)
{
ByteArrayOutputStream fbaos = new ByteArrayOutputStream();
bufferedImage = videoCap.getOneFrame();
ImageIO.write(bufferedImage, formatType, fbaos);
f = new Frame(fbaos.toByteArray());
oos.writeObject(f);
oos.flush();
bufferedImage.flush();
// Thread.sleep(33);
}
}
catch (IOException e)
{
e.printStackTrace();
}
// catch (InterruptedException e)
// {
// e.printStackTrace();
// }
}
}
答案 1 :(得分:0)
TCP传输层是可靠的,不会丢失数据包,因此可能会有数据包延迟,您可以使用DatagramSocket
代替ServerSocket
和Socket
通过{{ 3}}协议。
通过DatagramSocket
对服务器和客户端进行采样:
import java.io.IOException;
import java.net.DatagramPacket;
import java.net.DatagramSocket;
public class smallserver {
public static void main(String[] args) throws IOException {
string host = "127.0.0.1";
int port = 5252;
byte buf[] = new byte[2];
byte send[] = { 13, 18 };
//server
DatagramSocket serverSocket = new DatagramSocket(port);
DatagramPacket receivePacket = new DatagramPacket(buf, 2);
serverSocket.receive(receivePacket);
// client
DatagramSocket clientSocket = new DatagramSocket(host, port);
DatagramPacket sendPacket = new DatagramPacket(send, 2, clientSocket.getAddress(), clientSocket.getPort());
clientSocket.send(sendPacket);
}
}