Question

我找到了应用程序代码，它（理论上）接收视频流并在VideoView对象上显示。

package com.example.cameraapp;

import android.net.Uri;
import android.os.Bundle;
import android.view.View;
import android.app.Activity;
import android.view.Menu;
import android.view.MenuItem;
import android.widget.MediaController;
import android.widget.VideoView;
import android.support.v4.app.NavUtils;

public class Camera extends Activity {
public VideoView mVideoView;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_camera);

    String LINK = "192.168.1.102:9889";
    setContentView(R.layout.activity_camera);
    VideoView videoView = (VideoView) findViewById(R.id.videoView1);
    MediaController mc = new MediaController(this);
    mc.setAnchorView(videoView);
    mc.setMediaPlayer(videoView);
    Uri video = Uri.parse(LINK);
    videoView.setMediaController(mc);
    videoView.setVideoURI(video);
    videoView.start();


}

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    getMenuInflater().inflate(R.menu.activity_camera, menu);
    return true;
}

}

但是，当我运行VLC播放器时 - ＆gt; Stream - ＆gt; Http端口9889 - ＆gt;转码MPEG-2 NO SOUND出现声明“不幸，无法显示此视频文件”。我试过rtsp，转码H.264，但它没有帮助。有谁知道它为什么不起作用？

Android网络摄像头流媒体

0 个答案: