Question

我有一个矩阵X，其主要对角线的最大值。首先，想要对第一行进行采样，并沿第i行选择最大值，不包括主对角线值，即max！= X [i，i]。

下面的代码通常会产生结果但通常会出错： Error in if (MAX < l[k]) { : missing value where TRUE/FALSE needed

# initial values
n = 10
pop = runif(n,min =0,max =1)
D = matrix(rnorm(n*n,0,0.2),nrow=n)

str_mat = abs(D)
for (l in 1:n) {
  str_mat[l,l] = 1
}

int_mat = matrix(rbinom(n*n,1,z),n,n) ##z takes the values 0.1 - 0.9
for (j in 1:n) {
  int_mat[j,j] = 1
}

X = (int_mat*str_mat)*pop
b = c(1:n)  #creating a vector with the length being the dimensions of the matrix
a = sample(b,1)## sampling one value from the vector
if (sum(int_mat[a,])< n)
{
    ### int_mat is a binary matrix
    break
}}

l = X[a,]

## Ensuring the maximum value picked is not on the main diagonal
MAX = 0
j = 1
for (k in 1:length(l)) {
  if(k!=a) {
    if (MAX<l[k]) {
      MAX = l[k]
      j = k
    }
  }
}

Answer 1

感谢大家的贡献。我想出了如何解决这个问题。如下所示;

X=(int_mat*str_mat)*pop    ## creating a matrix of interaction, competition strength and  population densities             

repeat{
  IntRowsums=rowSums(int_mat)
  introwsums_greater=which(IntRowsums>2,arr.ind = T)
  if (length(introwsums_greater)>1){
    a= sample(introwsums_greater,1)
  }else{
    a=introwsums_greater
  }
  if (sum(int_mat[a,])< n){
    break
  }}

q= ABX[a,]
j_k=which(q!=q[a] & q!=0,arr.ind = T)     ## from the sampled row in str_mat check the position of all zeros
k=sample(j_k,1)

采样矩阵上的最大值，不包括主对角线上的值

1 个答案: