我有一个数据框,其中包含一个包含多个值的列,这些值由以分号分隔的基因名称同义词组成:
score <- c("32.01","19.5","18.0")
symbol <- c("30 kDa adipocyte complemen related protein","AAT1","Cachectin")
synonym <- c("30 kDa adipocyte complemen related protein; 30 kDa adipocyte complement-related protein; ACDC; ACRP30; ADIPOQ; APM-1; APM1; Adipocyte C1Q and collagen domain containing","AAT1; AAT1; ALT-1; ALT1; Alanine aminotransferase; Alanine aminotransferase 1; GPT 1; GPT1; Glutamate pyruvate transaminase; Glutamic--alanine transaminase 1; Glutamic--pyruvic transaminase 1","Cachectin; TNF alpha; TNF-a; TNFA; TNFSF-2; TNFSF2; TNFalpha; Tumor necrosis factor; Tumor necrosis factor ligand superfamily member 2; Tumor necrosis factor precursor; tumor necrosis factor alpha")
df <- data.frame(score, symbol, synonym, stringsAsFactors=FALSE)
这是数据挖掘的原始输出。我将数据中的官方基因符号映射到Entrez ID。符号列通常不包含基因符号,因此我必须提取所有同义词(通常,列表中有正式符号)。我想要跟踪行号的目标是,一旦我将所有符号映射到Entrez ID,我就可以识别那些没有映射的行。
我目前正在使用strsplit和unlist来解析同义词,但我忘记了每个同义词来自哪一行:
tmp <- data.frame(unlist(strsplit(as.character(df$synonym), "; ")))
我想要的是这样的东西:
originalRow <- c(1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,3,3,3)
cbind(tmp, originalRow)
synonym originalRow
1 30 kDa adipocyte complemen related protein 1
2 30 kDa adipocyte complement-related protein 1
3 ACDC 1
4 ACRP30 1
5 ADIPOQ 1
6 APM-1 1
7 APM1 1
8 Adipocyte C1Q and collagen domain containing 1
9 AAT1 2
10 AAT1 2
11 ALT-1 2
12 ALT1 2
13 Alanine aminotransferase 2
14 Alanine aminotransferase 1 2
15 GPT 1 2
16 GPT1 2
17 Glutamate pyruvate transaminase 2
18 Glutamic--alanine transaminase 1 2
19 Glutamic--pyruvic transaminase 1 2
20 Cachectin 3
21 TNF alpha 3
22 TNF-a 3
23 TNFA 3
24 TNFSF-2 3
25 TNFSF2 3
26 TNFalpha 3
27 Tumor necrosis factor 3
28 Tumor necrosis factor ligand superfamily member 2 3
29 Tumor necrosis factor precursor 3
30 tumor necrosis factor alpha 3
任何建议都将不胜感激!
答案 0 :(得分:1)
在这里,您可以拆分每一行,将行的值与行号组合到一个data.frame中,然后将所有这些data.frames绑定在一起。你可以用
做到这一点do.call("rbind", Map(data.frame,
synonym=strsplit(as.character(df$synonym), ";"),
origRow=seq_along(df$synonym))
)
答案 1 :(得分:0)
另一种方法是将同义词存储在列表中,然后可以迭代以与符号数组进行比较。在单个列表元素中工作不需要跟踪原始行号。这也将修剪空白以进行比较。
lst <- lapply(synonym, function(x) trimws(unlist(strsplit(x, ";"))))
lapply(lst, setdiff, symbol) # return values not in symbol array
[[1]]
[1] "30 kDa adipocyte complement-related protein" "ACDC"
[3] "ACRP30" "ADIPOQ"
[5] "APM-1" "APM1"
[7] "Adipocyte C1Q and collagen domain containing"
[[2]]
[1] "ALT-1" "ALT1" "Alanine aminotransferase"
[4] "Alanine aminotransferase 1" "GPT 1" "GPT1"
[7] "Glutamate pyruvate transaminase" "Glutamic--alanine transaminase 1" "Glutamic--pyruvic transaminase 1"
[[3]]
[1] "TNF alpha" "TNF-a"
[3] "TNFA" "TNFSF-2"
[5] "TNFSF2" "TNFalpha"
[7] "Tumor necrosis factor" "Tumor necrosis factor ligand superfamily member 2"
[9] "Tumor necrosis factor precursor" "tumor necrosis factor alpha"