Question

select max(total), date
from (select sum(total) as total, date as date
      from canteen
      group by date) as max

我想从表中选择最高销售额和最高销售日期。

使用我的查询显示此错误。

异常，错误代码8,120，SQLState S0001]列＆＃39; max.date＆＃39;是在选择列表中无效，因为它不包含在任何一个中聚合函数或GROUP BY子句。

Answer 1

您可以使用order by，将您的数据设置为按销售顺序降序并获取第一行。

如果您想按日期结果，那么您可以使用ROW_NUMBER（）

select TOP(1) total, date
from 
(
  select sum(total) as total, date as date
  from canteen
  group by date
) as max
Order by todal desc

Answer 2

这将返回达到最大销售总额的所有日期。 Here是一个演示。

; with x as (
    select sum(total) as total, date from canteen group by date
)
, y as (
    select dr = dense_rank() over(order by total desc), *
    from x
)
select * from y where dr = 1

Answer 3

如果你想得到所有日期的最大值（总数），这里就是

;with temp as 
(
   select sum(total) as total, date as date
   from canteen
   group by date
)
SELECT TOP 1 WITH TIES *
FROM temp 
ORDER BY temp.total desc

Answer 4

您忘记添加分组＆amp;在您的外部查询中排序。我已修改它以按降序显示所有销售。所以最高的销售将是最重要的。

select max(total) total, date
from (select sum(total) as total, date as date
      from canteen
      group by date) as max
group by date 
order by total desc

从sql表中选择带日期的最高销售额

4 个答案: