我现在有这样的查询:
SELECT DATE_FORMAT(`Datum`, '%e %M') AS `DATE`, tag AS `TAG`, value AS `VALUE`, addedTs as `addedTs`
FROM dailyMessage
INNER JOIN `psttodo-uit`
ON dailyMessage.Code = `psttodo-uit`.`Hostess Code`
WHERE Code = "010"
我知道得到这样的结果:
DATE TAG VALUE addedTs
4 April calls 3 2014-04-04 20:32:39
4 April endTS 2014-04-04 22:40:55 2014-04-04 22:40:55
4 April kmstart 32 2014-04-04 18:34:37
4 April kmstop 34434334 2014-04-04 18:35:30
4 April startTS 2014-04-04 18:35:00 2014-04-04 18:35:00
4 April visits 6 2014-04-04 22:40:53
5 April endTS 2014-04-05 01:37:41 2014-04-05 01:37:41
5 April kmstart 30 2014-04-05 01:37:41
5 April startTS 2014-04-05 01:13:25 2014-04-05 01:13:25
5 April visits 1 2014-04-05 01:13:23
7 April authorizations 4 2014-04-07 22:34:37
7 April calls 9 2014-04-07 23:18:28
7 April endTS 2014-04-07 23:35:32 2014-04-07 23:35:32
7 April kmstart 42 2014-04-07 18:10:43
7 April kmstop 55 2014-04-07 19:37:42
7 April startTS 2014-04-07 10:45:18 2014-04-07 10:45:18
7 April visits 6 2014-04-07 23:35:31
8 April endTS 2014-04-08 11:24:28 2014-04-08 11:24:28
8 April startTS 2014-04-08 11:24:28 2014-04-08 11:24:28
现在我还要从psttodo-uit表中选择最高日期。这就是我想要做的事情:
在psttodo-uit
表格中有一个Hostess Code
(== Code in my WHERE clausule
)。 datetype afgewerkt tablet datum
表中还有一个datetime
字段。
日期变化如下:
2014-04-04 11:41:22
2014-04-03 17:20:01
2014-04-01 15:12:08
2014-04-07 22:20:47
2014-04-08 11:21:18
现在,当我进行查询时,我想选择特定日期的最长时间。我试过这样的话:
SELECT DATE_FORMAT(`Datum`, '%e %M') AS `DATE`, tag AS `TAG`, value AS `VALUE`, addedTs as `addedTs`, MAX(`afgewerkt tablet datum`) AS `TimeSorE`
FROM dailyMessage
INNER JOIN `psttodo-uit`
ON dailyMessage.Code = `psttodo-uit`.`Hostess Code`
WHERE Code = "010"
但后来我明白了:
4 April calls 3 2014-04-04 20:32:39 2014-04-09 11:49:42
两个问题:
有人可以帮我解决这个问题吗?
更新
我尝试了什么:
SELECT DATE_FORMAT(`Datum`, '%e %M') AS `DATE`, tag AS `TAG`, value AS `VALUE`, addedTs as `addedTs`, MAX(`afgewerkt tablet datum`) AS `TimeSorE`
FROM dailyMessage
INNER JOIN `psttodo-uit`
ON dailyMessage.Code = `psttodo-uit`.`Hostess Code`
WHERE Code = "010"
GROUP BY DATE_FORMAT(`Datum`, '%e %M')
给我这个:
4 April calls 3 2014-04-04 20:32:39 2014-04-09 15:46:04
5 April endTS 2014-04-05 01:37:41 2014-04-05 01:37:41 2014-04-09 15:46:04
7 April authorizations 4 2014-04-07 22:34:37 2014-04-09 15:46:04
8 April endTS 2014-04-08 11:24:28 2014-04-08 11:24:28 2014-04-09 15:46:04
但是我需要它们(包括所有标签)。
答案 0 :(得分:1)
SELECT DATE_FORMAT(`Datum`, '%e %M') AS `DATE`, GROUP_CONCAT(tag) AS `TAG`, value AS `VALUE`, addedTs as `addedTs`, MAX(`afgewerkt tablet datum`) AS `TimeSorE`
FROM dailyMessage
INNER JOIN `psttodo-uit`
ON dailyMessage.Code = `psttodo-uit`.`Hostess Code`
WHERE Code = "010"
GROUP BY DATE_FORMAT(`Datum`, '%e %M')
如果您需要将结果集作为单独的行,请尝试使用
SELECT A.DATE ,A.CODE,TAG,addedTs,TimeSorE
(
SELECT DATE_FORMAT(`Datum`, '%e %M') AS `DATE`,dailyMessage.Code AS CODE
MAX(`afgewerkt tablet datum`) AS `TimeSorE`
FROM dailyMessage
INNER JOIN `psttodo-uit`
ON dailyMessage.Code = `psttodo-uit`.`Hostess Code`
WHERE Code = "010"
GROUP BY DATE_FORMAT(`Datum`, '%e %M')
) A , dailyMessage B
WHERE
A.CODE = B.CODE AND
A.DATE = B. DATE_FORMAT(`Datum`, '%e %M')
答案 1 :(得分:0)
这对我来说绝对有用:
SELECT
DATE_FORMAT(`Date`, '%e %M') AS `DATE`,
tag AS `TAG`,
value AS `VALUE`,
addedTs as `addedTs`,
MAX(`afgewerkttabletdatum`) AS `TimeSorE`
FROM Test
GROUP BY DATE_FORMAT(`Date`, '%e %M')
以下是一个例子:
答案 2 :(得分:0)
我认为这会奏效:
SELECT DATE_FORMAT(`Datum`, '%e %M') AS `DATE`,
tag AS `TAG`,
value AS `VALUE`,
addedTs AS `addedTs`,
t2.`TimeSorE`
FROM dailyMessage
INNER JOIN (SELECT `Hostess Code`,
MAX(`afgewerkt tablet datum`) AS `TimeSorE`
FROM `psttodo-uit`
GROUP BY `Hostess Code`) t2 ON dailyMessage.Code = t2.`Hostess Code`
WHERE Code = "010"