基本上我想要的是用实际实体替换文本中的所有代词。
// Path to the folder with models extracted from `stanford-corenlp-3.7.0-models.jar`
var jarRoot = ...
// Text for processing
var text = "Kosgi Santosh sent an email to Stanford University. He didn't get a reply.";
// Annotation pipeline configuration
var props = new Properties();
props.setProperty("annotators", "tokenize, ssplit, pos, lemma, ner, parse, dcoref");
props.setProperty("ner.useSUTime", "0");
// We should change current directory, so StanfordCoreNLP could find all the model files automatically
var curDir = Environment.CurrentDirectory;
Directory.SetCurrentDirectory(jarRoot);
var pipeline = new StanfordCoreNLP(props);
Directory.SetCurrentDirectory(curDir);
// Annotation
var annotation = new Annotation(text);
pipeline.annotate(annotation);
var graph = annotation.get(new CorefChainAnnotation().getClass());
Console.WriteLine(graph);
到目前为止,我只能找到如何"漂亮的印刷"它,但我想进一步处理" graph"的结果,但我不知道如何从" annotation.get(new CorefChainAnnotation()。getClass())实际解析结果&#34 ;.在Java中,据说它将返回Map<整数,CorefChain>,但我不知道它应该如何在C#中工作。
你有什么想法吗?
答案 0 :(得分:0)
获得注释后,您可以通过投射获得图表。
Map graph = (Map)document.get(new CorefCoreAnnotations.CorefChainAnnotation().getClass());
var entrySetValues = graph.entrySet();
Iterator it = entrySetValues.iterator();
while (it.hasNext())
{
Map.Entry kvpair = (Map.Entry)it.next();
CorefChain corefChain = (CorefChain)kvpair.getValue();
var mentionsList = corefChain.getMentionsInTextualOrder() as ArrayList;
foreach (CorefMention mention in mentionsList)
{
string noun = mention.mentionSpan;
// do other stuff
}
it.remove();
}
对于C#,我们的想法是首先正确地转换对象,从转换对象中获取列表作为ArrayList,在arraylist上循环并再次正确地转换对象。