Question

我有一个上传文件的表单。我的控制器： -

public class ConsentController {
@Autowired
private ConsentRepository consentRepository;
private static String UPLOADED_FOLDER = "E://java//files//"; //this directory is used to save the uploaded file
public String filepath;
@RequestMapping(value="/addconsent",headers=("content-type=multipart/*"),method = RequestMethod.POST)
public String addConsent(@RequestParam("consentstatus") String consentStatus,
                         @RequestParam("file")MultipartFile file,
                         @RequestParam("pid")Participants pid,
                         @RequestParam("participantsid") long participantsid,
                         @RequestParam("userid")User userid,
                         @RequestParam("consentid") long consentid
                         ){
  if(consentRepository.findByParticipants(pid)==null){
      if(file.isEmpty()) {
          Consent consent = new Consent(consentStatus,"null",userid,pid);
          consentRepository.save(consent);
      }
      else{
          try {

              // Get the file and save it somewhere
              byte[] bytes = file.getBytes();
              Path path = Paths.get(UPLOADED_FOLDER + file.getOriginalFilename());
              Files.write(path, bytes);


              //get the path of the saved filed
              String filename = file.getOriginalFilename();
              String filepath = Paths.get(UPLOADED_FOLDER, filename).toString();
              this.filepath=filepath;
              Consent consent=new Consent(consentStatus,this.filepath,userid,pid);
              consentRepository.save(consent);
          }catch (Exception ex){
              System.out.println("Error"+ex.getMessage());
          }
      }
  }

此代码完美上传并将我上传的文件存储在电子硬盘中。但现在我想在将文件保存到目录之前压缩文件。现在，如果我上传images.jpg它上传images.jpg。我想将这个images.jpg保存为（任何名称），但是采用压缩格式。

Answer 1

以下是oracle article

的拉链演示

import java.io.*;
import java.util.zip.*;

public class Zip {
static final int BUFFER = 2048;
public static void main (String argv[]) {
  try {
     BufferedInputStream origin = null;
     FileOutputStream dest = new 
       FileOutputStream("c:\\zip\\myfigs.zip");
     ZipOutputStream out = new ZipOutputStream(new 
       BufferedOutputStream(dest));
     //out.setMethod(ZipOutputStream.DEFLATED);
     byte data[] = new byte[BUFFER];
     // get a list of files from current directory
     File f = new File(".");
     String files[] = f.list();

     for (int i=0; i<files.length; i++) {
        System.out.println("Adding: "+files[i]);
        FileInputStream fi = new 
          FileInputStream(files[i]);
        origin = new 
          BufferedInputStream(fi, BUFFER);
        ZipEntry entry = new ZipEntry(files[i]);
        out.putNextEntry(entry);
        int count;
        while((count = origin.read(data, 0, 
          BUFFER)) != -1) {
           out.write(data, 0, count);
        }
        origin.close();
     }
     out.close();
  } catch(Exception e) {
     e.printStackTrace();
  }
}
}

Answer 2

您需要使用ZipOutputStream在java中将数据写入zip。这是一个例子：

<int-jms:message-driven-channel-adapter id="jmsInEldm"container="publishmessageListenerContainer"
    channel="IncomingELDMChannel"/>

这是教程，展示了如何在java中压缩和解压缩文件 http://www.oracle.com/technetwork/articles/java/compress-1565076.html

上传文件，压缩并将其保存到内存中

2 个答案: