上传Zip文件并解压缩Zip

时间:2014-03-12 15:07:14

标签: php file-upload zip extract

我有一个表单(HTML),它将文件提交给PHP脚本,该脚本将文件重命名为ZIP,将其存储在一个文件夹(随机名称)中,然后提取该文件。

文件上传。 文件夹已正确创建。 该文件被正确重命名。

拉链的提取失败。

这是我的表格:

<form action="up.php" method="post" enctype="multipart/form-data" name="form1" id="form1">

Select file 
<input name="ufile" type="file" id="ufile" size="50" />

<input type="submit" name="Submit" value="Upload" />

 </form>

这是PHP脚本 - up.php

$file_name = $HTTP_POST_FILES['ufile']['name'];
$random_digit=rand(0000,9999);
$new_file_name=$random_digit.".zip";
mkdir($random_digit, 0777, true);

$path= $random_digit.'/'.$new_file_name;
if($ufile !=none)
 {
    if(copy($HTTP_POST_FILES['ufile']['tmp_name'], $path))
 {
 echo "The upload is successful<BR/>"; 
 echo "File Renamed to: ".$new_file_name." for processing.<BR/>"; 
 echo "File Size :".$HTTP_POST_FILES['ufile']['size']."<BR/>"; 
 echo "<strong><a style='color:#6A8DBC; text-decoration:none' href='".$link_address."'>Proceed to the next phase of the importation of data to the system</a></strong></br>";
  }
 else
  {
   echo "Error";
   }
 }

  $zip = new ZipArchive;
  $res = $zip->open($new_file_name);
  if ($res === TRUE) {
     $zip->extractTo($random_digit.'/');
     $zip->close();
     echo 'extraction successful';
     } else {
     echo 'extraction error';
     }

是防止提取的文件夹的模式吗?据我所知,没有语法错误。

2 个答案:

答案 0 :(得分:5)

<?php 

function rmdir_recursive($dir) {
    foreach(scandir($dir) as $file) {
       if ('.' === $file || '..' === $file) continue;
       if (is_dir("$dir/$file")) rmdir_recursive("$dir/$file");
       else unlink("$dir/$file");
   }

   rmdir($dir);
}

if($_FILES["zip_file"]["name"]) {
    $filename = $_FILES["zip_file"]["name"];
    $source = $_FILES["zip_file"]["tmp_name"];
    $type = $_FILES["zip_file"]["type"];

    $name = explode(".", $filename);
    $accepted_types = array('application/zip', 'application/x-zip-compressed', 'multipart/x-zip', 'application/x-compressed');
    foreach($accepted_types as $mime_type) {
        if($mime_type == $type) {
            $okay = true;
            break;
        } 
    }

    $continue = strtolower($name[1]) == 'zip' ? true : false;
    if(!$continue) {
        $message = "The file you are trying to upload is not a .zip file. Please try again.";
    }

  /* PHP current path */
  $path = dirname(__FILE__).'/';  // absolute path to the directory where zipper.php is in
  $filenoext = basename ($filename, '.zip');  // absolute path to the directory where zipper.php is in (lowercase)
  $filenoext = basename ($filenoext, '.ZIP');  // absolute path to the directory where zipper.php is in (when uppercase)

  $targetdir = $path . $filenoext; // target directory
  $targetzip = $path . $filename; // target zip file

  /* create directory if not exists', otherwise overwrite */
  /* target directory is same as filename without extension */

  if (is_dir($targetdir))  rmdir_recursive ( $targetdir);


  mkdir($targetdir, 0777);


  /* here it is really happening */

    if(move_uploaded_file($source, $targetzip)) {
        $zip = new ZipArchive();
        $x = $zip->open($targetzip);  // open the zip file to extract
        if ($x === true) {
            $zip->extractTo($targetdir); // place in the directory with same name  
            $zip->close();

            unlink($targetzip);
        }
        $message = "Your .zip file was uploaded and unpacked.";
    } else {    
        $message = "There was a problem with the upload. Please try again.";
    }
}


?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Unzip a zip file to the webserver</title>
</head>

<body>
<?php if($message) echo "<p>$message</p>"; ?>
<form enctype="multipart/form-data" method="post" action="">
<label>Choose a zip file to upload: <input type="file" name="zip_file" /></label>
<br />
<input type="submit" name="submit" value="Upload" />
</form>
</body>
</html>

答案 1 :(得分:3)

$res = $zip->open($path)

当您将文件移至$path时,您需要对$path

上的文件进行操作