我的问题是我想用不同颜色绘制这个结构的0,0,0点而不是所有其他点。但是绘图只显示所选颜色的轮廓,并且该球的内部仍然是与其他。 我不明白这是如何运作的。
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np
fig = plt.figure()
ax = fig.gca(projection='3d')
ax.set_aspect("equal")
for x in range(-count,count+1):
for y in range(-count,count+1):
for z in range(-count,count+1):
if x == 0 and y == 0 and z == 0:
ax.scatter(x,y,z, color="g",s=100) #here is the problem
elif ((x+y+z+3*count)%2) == 0:
ax.scatter(*zip([x,y,z]), color="r")
else:
ax.scatter(*zip([x,y,z]), color="b")
plt.show()
答案 0 :(得分:4)
您可以使用参数edgecolor
和facecolor
来设置边和面的颜色。
ax.scatter(x,y,z, s=100, edgecolor="r", facecolor="gold")
或者,您可以使用参数c
直接设置颜色,
ax.scatter(x,y,z, s=100, c="limegreen")
或设置应通过颜色图表示颜色的值范围。最后一种方法还允许将所有点放在一个散点图中,如下所示:
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np
fig = plt.figure()
ax = fig.gca(projection='3d')
ax.set_aspect("equal")
count = 2
x = range(-count,count+1)
X,Y,Z = np.meshgrid(x,x,x)
c = np.zeros_like(X, dtype=np.float)
c[((X+Y+Z+3*count)%2) == 0] = 0.5
c[count,count,count] = 1
s = np.ones_like(X)*25
s[count,count,count] = 100
ax.scatter(X,Y,Z, c=c,s=s, cmap="brg")
plt.show()