Question

这是我的问题：

SELECT rid
FROM relations
WHERE rootid IN (736, 781) 
GROUP BY rid HAVING COUNT(rid) = 2");

我正试图在Laravel中实现它。我怎样才能做到这一点？（“查询构建器和雄辩的方法对我来说都很好”）

这不起作用：（它会抛出“出错的地方”）

DB::table('relations')
->select('')
->whereRaw('rootid IN (736, 781)')
->groupBy('rid')
->havingRaw('COUNT(rid) = 2')
->get();

Answer 1

$sql = 'SELECT rid FROM relations WHERE rootid IN (736, 781) 
         GROUP BY rid HAVING COUNT(rid) = 2)';

$result = DB::SELECT($sql);

Answer 2

你可以试试这个

DB::table('relations')
    ->select(DB::raw('count(*) as user_count, status'))
    ->whereRaw('rootid IN (736, 781)')
    ->groupBy('rid')
    ->having(DB::Raw('COUNT(rid) = 2'))
    ->get();

Answer 3

试试这个

DB::table('relations')
->select(DB::raw('count(*) as user_count, status'))
->whereRaw('rootid IN (736, 781)')
->groupBy('rid')
->having(DB::Raw('COUNT(rid) = 2'))
->get();

Answer 4

试试这个

DB::table('relations')
->whereIn('rootid', [736, 781])
->groupBy('rid')
->havingRaw('COUNT(rid) = 2')
->get();

Answer 5

试试这个

DB::select(DB::raw('SELECT rid
FROM relations
WHERE rootid IN (736, 781) 
GROUP BY rid HAVING COUNT(rid) = 2")'));

如何在Laravel中将查询编写为raw？

5 个答案: