Question

我是Laravel的初学者。我可以在原始PHP中编写查询。现在我想在Laravel框架中编写它。我已阅读文档并尝试到目前为止：

在原始PHP中：

SELECT count(*)/(TIMESTAMPDIFF(YEAR,'2016-01-01 00:00:00',now())+1) as avg from buyer  where created_at >= '2016-01-01 00:00:00';

与Laravel一起尝试：

public function index(){
    //
    $yrUserReg = DB::table('buyer')
                    -> SELECT (DB::raw (count('*')/("TIMESTAMPDIFF(YEAR,'2016-01-01 00:00:00',now())+1"))) 
                    -> AS ('avg') 
                    -> WHERE ("created_at >= '2016-01-01 00:00:00'");
   return view('userflow',compact($yrUserReg));                 
}

但它给我一个错误： Division by Zero 。我找不到任何解决方法。提前致谢。任何帮助将不胜感激!!

Answer 1

以下是完整构建的查询：

$yrUserReg =  DB::table('buyer')
                ->select(DB::raw("(count('*')/(TIMESTAMPDIFF(YEAR,'2016-01-01 00:00:00',now())+1)) as avg"))
                ->where('created_at', '>=', '2016-01-01 00:00:00')
                ->get();

如何在Laravel 5.1中编写原始查询？

1 个答案: