Question

我想在查询中为3个变量添加别名，total_time_taken和average以及request_count。

平均值是为了计算total_time_taken / request_count以返回average，但它会给我一个语法错误

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'select(created_at, assigned_at, SUM(TIMESTAMPDIFF(SECOND, requests.created_at, r' at line 4

查询如下。

select
    *,
    COUNT(*) as request_count,
    select(created_at, assigned_at, SUM(TIMESTAMPDIFF(SECOND, requests.created_at, requests.assigned_at)) from requests) as total_time_taken,
    total_time_taken / request_count as average
from
    `requests`
where
    `deleted_at` is null
and
    `submitted_at` >= '2017-03-30 00:00:00'
and
    `requests`.`deleted_at` is null
group by
    `engineer_id`
limit 5

Answer 1

我没有看到子查询的重点，为什么不把每个工程师汇总的总和拿走？另外，你正在SELECT *使用GROUP BY，这通常不起作用，而且通常是错误的，因为它会包含非聚合列。相反，只需选择engineer_id或其他列的汇总。

SELECT
    engineer_id,
    COUNT(*) AS request_count,
    SUM(TIMESTAMPDIFF(SECOND, created_at, assigned_at)) AS total_time_taken,
    SUM(TIMESTAMPDIFF(SECOND, created_at, assigned_at)) /
    COUNT(*) AS average
FROM requests
WHERE deleted_at IS NULL AND
      submitted_at >= '2017-03-30 00:00:00' AND
      deleted_at IS NULL
GROUP BY engineer_id
LIMIT 5

Sub在MySQL查询中选择

1 个答案: