我在下面有一个SQL查询。
SELECT sched_date, sched_name, employee_name from tbl_schedule
返回此结果:
sched_date sched_name employee_name
2017-04-01 09:00 AM - 06:00 PM M.G.Cave
2017-04-01 09:00 AM - 06:00 PM L.C.Manalo
2017-04-01 11:00 AM - 8:00 PM R.M.Jakosalem
2017-04-01 11:00 AM - 8:00 PM S.D.Dela Cruz
2017-04-02 Rest Day M.G.Cave
2017-04-02 Rest Day L.C.Manalo
2017-04-02 Rest Day R.M.Jakosalem
2017-04-02 Rest Day S.D.Dela Cruz
我希望员工按日期和时间表计算。我想要的结果是:
2017-04-01 09:00 AM - 06:00 PM 2 employees
2017-04-01 11:00 AM - 8:00 PM 2 employees
2017-04-02 Rest Day 4 employees
提前谢谢。
答案 0 :(得分:2)
GROUP BY
,sched_date
和sched_name
上的COUNT(*)
会为您提供所需的结果:
SELECT
sched_date,
sched_name,
COUNT(*) AS employees
from
tbl_schedule
GROUP BY
sched_date,
sched_name
答案 1 :(得分:1)
尝试以下查询:
SELECT *
FROM
(
SELECT sched_date, sched_name, COUNT(*) AS employees
FROM tbl_schedule
GROUP BY sched_date,sched_name
) A