Question

我试图在php中找到一个方法，将所有相关的搜索返回结果从mysql DB连接成一个用逗号分隔的单个字符串。请参阅下面的DB表php输出格式和php代码。

海滩桌：

$sortBy

Beach_Act_Type表：

bname    length  city_name
Beach A  4       City Z
Beach B  3       City X
Beach C  7       City E

输出I＆＃39; m寻找：

bname        act_type
Beach A      Swimming
Beach A      Surfing
Beach B      Surfing
Beach C      Swimming
Beach C      Fishing
Beach C      Surfing

而不是这种输出格式：

`beach`.`bname`    `beach_act_type`.`act_type`  
 Beach C           Swimming, Fishing, Surfing

我的PHP代码：

`beach`.`bname`    `beach_act_type`.`act_type`  
 Beach C           Swimming 
 Beach C           Fishing  
 Beach C           Surfing

Answer 1

您正在寻找的功能是GROUP_CONCAT。

SELECT 
    `beach`.`bname`, 
    GROUP_CONCAT(`beach_act_types`.`act_type`) types
FROM
    `beach`
INNER JOIN
    `beach_act_types` ON
        `beach`.`bname` = `beach_act_types`.`bname`
WHERE
    `beach`.`bname` = '$search'

PS。应该警告您存在SQL注入，请考虑切换到准备好的语句。

Answer 2

你只是在捣乱两个单独的表数据，它们不会给你你想要的结果，请尝试下面的代码你不能得到＆＃34;，＆＃34;在不同的表数据中。试试这个，

    <?php $conn = new
  mysqli('localhost','test','','beachproject');
  if (!$conn) { die('DB Connection
  Error'); }
  $search = $_POST['search'];
  $search_sql="select `beach`.`bname`,
 `beach_act_type`.`act_type` from
 `beach` inner join `beach_act_types` on
 `beach`.`bname`=`beach_act_type`.`
  bname` where
  `beach`.`bname`='$search'";
 $search_query=$conn
 >query($search_sql); 
 if ($search_query->num_rows > 0) { 
 while($row = $search_query
 >fetch_assoc()) { echo "<table
 border='1' cellpadding='4'>
 <tr> <th>Beach Name</th> <th>Beach
 Activity Allowed</th> </tr>"; echo "<tr>";
 echo "<td>" . $row['bname'] . , .
 $row['act_type']"</td>"; echo "</tr>";
 echo "</table>"; } } else { echo "No
 Search Results"; } ?>

PHP搜索结果连接

2 个答案: