搜索结果错误

Question

这是我的搜索查询，如果没有结果匹配，我该如何显示错误， 请帮忙

 $sql="SELECT  * FROM course WHERE course_name LIKE '%" . $search_name .  "%'";
              //-run  the query against the mysql query function
              $result=mysql_query($sql);

Answer 1

$sql="SELECT  * FROM course WHERE course_name LIKE '%" . $search_name .  "%'";
              //-run  the query against the mysql query function
$result=mysql_query($sql);

if(mysql_num_rows($result) < 1)
{
    echo 'There were no results.';
}

Answer 2

if(mysql_num_rows($sql)=="0")
{
echo "----------------"; //your code here
}