Question

我创建了一个显示地点列表的应用程序，我创建了一个搜索对话框，其中用户将键入edittext，以便他/她找到所需的位置。但是我收到了一个错误，我将在下面发布。

尝试在com.example.ubaldo.myapplication.Place $ 4 $ 1.onClick（Place.java:221）上的空对象引用上调用虚拟方法'android.text.Editable android.widget.EditText.getText（）'

这是我的代码中的第221行

GetSearchPlace = dbhelper.getPlaceSearch(placeLocationEditText.getText().toString());

这是我的DatabaseHelper

public List<PlaceModel> getPlaceSearch(String location) {
        List<PlaceModel> search = new ArrayList<PlaceModel>();

        String selectQuery = "SELECT * FROM listing_place where province_name like '" + location + "'";
        SQLiteDatabase db = this.getReadableDatabase();
        Cursor cursor = db.rawQuery(selectQuery, null);

        if (cursor.moveToFirst()) {
            do {
                PlaceModel pm = new PlaceModel();
                pm.setlisting_title(cursor.getString(cursor.getColumnIndex(KEY_PLACE)));
                search.add(pm);
            }
            while (cursor.moveToNext());
        }
        cursor.close();
        return search;
    }

这是我的主要活动

 placeLocationEditText = (EditText)findViewById(R.id.placelocation);

                Button button = (Button) dialog.findViewById(R.id.btnplacesearch);

                button.setOnClickListener(new View.OnClickListener() {
                    @Override
                    public void onClick(View v) {
                        dialog.dismiss();

                        PlaceListView = findViewById(R.id.placelayout);
                        ViewGroup parent = (ViewGroup) PlaceListView.getParent();
                        parent.removeView(PlaceListView);
                        PlaceSearchView = getLayoutInflater().inflate(R.layout.searchresult_place, parent, false);
                        parent.addView(PlaceSearchView);

                        GetSearchPlace = dbhelper.getPlaceSearch(placeLocationEditText.getText().toString());
                        lv2 = (ListView) findViewById(R.id.searchplace_list);
                        lv2.setAdapter(new ViewAdapterSearchPlace());

Answer 1

替换

 placeLocationEditText = (EditText)findViewById(R.id.placelocation);

与

 placeLocationEditText = (EditText)dialog.findViewById(R.id.placelocation);

搜索结果Android SQLite出错

1 个答案: