import json
import requests
import urllib
url = "https://developers.google.com/qpx-express/v1/trips/search?key=<API_key>"
headers = {'content-type': 'application/json'}
params = {
"request": {
"slice": [
{
"kind": "qpxexpress#sliceInput",
"origin": "BOS",
"destination": "SFO",
"date": "2017-06-30"
}
],
"passengers": {
"kind": "qpxexpress#passengerCounts",
"adultCount": 1,
},
"refundable": "false",
"solutions": 20,
}
}
#jsonreq = json.dumps(params)
data = urllib.parse.urlencode(params)
binary_data = data.encode('utf-8')
req = urllib.request.Request(url, binary_data)
flight = urllib.request.urlopen(req)
response = flight.read()
print(response)
我正在尝试检索机票价格,但Google API一直给我提供HTTP错误403:禁止。
我已检查过我的Developers控制台,并启用了QPX Express API。另外,我已经生成了一个没有限制的API_key。
这是错误:
HTTPError Traceback (most recent call last)
<ipython-input-189-cc6dee70b145> in <module>()
31 binary_data = data.encode('utf-8')
32 req = urllib.request.Request(url, binary_data)
---> 33 flight = urllib.request.urlopen(req)
34 response = flight.read()
35 print(response)
C:\Anaconda3\lib\urllib\request.py in urlopen(url, data, timeout, cafile, capath, cadefault, context)
161 else:
162 opener = _opener
--> 163 return opener.open(url, data, timeout)
164
165 def install_opener(opener):
C:\Anaconda3\lib\urllib\request.py in open(self, fullurl, data, timeout)
470 for processor in self.process_response.get(protocol, []):
471 meth = getattr(processor, meth_name)
--> 472 response = meth(req, response)
473
474 return response
C:\Anaconda3\lib\urllib\request.py in http_response(self, request, response)
580 if not (200 <= code < 300):
581 response = self.parent.error(
--> 582 'http', request, response, code, msg, hdrs)
583
584 return response
C:\Anaconda3\lib\urllib\request.py in error(self, proto, *args)
508 if http_err:
509 args = (dict, 'default', 'http_error_default') + orig_args
--> 510 return self._call_chain(*args)
511
512 # XXX probably also want an abstract factory that knows when it makes
C:\Anaconda3\lib\urllib\request.py in _call_chain(self, chain, kind, meth_name, *args)
442 for handler in handlers:
443 func = getattr(handler, meth_name)
--> 444 result = func(*args)
445 if result is not None:
446 return result
C:\Anaconda3\lib\urllib\request.py in http_error_default(self, req, fp, code, msg, hdrs)
588 class HTTPDefaultErrorHandler(BaseHandler):
589 def http_error_default(self, req, fp, code, msg, hdrs):
--> 590 raise HTTPError(req.full_url, code, msg, hdrs, fp)
591
592 class HTTPRedirectHandler(BaseHandler):
HTTPError: HTTP Error 403: Forbidden
答案 0 :(得分:3)
您确定使用的是正确的网址吗?我最初和你有同样的问题,但发现下面的代码有效。我也在使用请求,这使得传递JSON更加直截了当。
import requests
url='https://www.googleapis.com/qpxExpress/v1/trips/search?key=%s'%google_api_key
params = {"request": {
"slice": [{"kind": "qpxexpress#sliceInput",
"origin": "BOS",
"destination": "SFO",
"date": "2017-06-30"}],
"passengers": {"kind": "qpxexpress#passengerCounts",
"adultCount": 1,},
"refundable": "false",
"solutions": 20,}
}
requests.post(url, json=params, headers = {'content-type': 'application/json'})