Question

我是一个Python新手，我一直试图让一些代码工作。

以下是代码，以及我不断得到的令人讨厌的错误。

import pywapi import string

google_result = pywapi.get_weather_from_google('Brisbane')

print google_result 
def getCurrentWather():
  city = google_result['forecast_information']['city'].split(',')[0]
  print "It is " + string.lower(google_result['current_conditions']['condition']) + " and
  " + google_result['current_conditions']['temp_c'] + " degree
  centigrade now in "+ city+".\n\n"
  return "It is " + string.lower(google_result['current_conditions']['condition']) + " and
  " + google_result['current_conditions']['temp_c'] + " degree
  centigrade now in "+ city

def getDayOfWeek(dayOfWk):
    #dayOfWk = dayOfWk.encode('ascii', 'ignore')
    return dayOfWk.lower()

def getWeatherForecast():
   #need to translate from sun/mon to sunday/monday
   dayName = {'sun': 'Sunday', 'mon': 'Monday', 'tue': 'Tuesday', 'wed': 'Wednesday', '    thu': 'Thursday', 'fri': 'Friday', 'sat':
   'Saturday', 'sun': 'Sunday'}

forcastall = []
for forecast in google_result['forecasts']:
    dayOfWeek = getDayOfWeek(forecast['day_of_week']);
    print " Highest is " + forecast['high'] + " and "+ "Lowest is " + forecast['low'] + " on " +  dayName[dayOfWeek]
    forcastall.append(" Highest is " + forecast['high'] + " and "+ "Lowest is " + forecast['low'] + " on " +  dayName[dayOfWeek])
return forcastall

现在是错误：

Traceback (most recent call last):   File
"C:\Users\Alex\Desktop\JAVIS\JAISS-master\first.py", line 5, in
<module>
import Weather   File "C:\Users\Alex\Desktop\JAVIS\JAISS-master\Weather.py", line 4, in
<module>
google_result = pywapi.get_weather_from_google('Brisbane')   File "C:\Python27\lib\site-packages\pywapi.py", line 51, in
get_weather_from_google
handler = urllib2.urlopen(url)   File "C:\Python27\lib\urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)   File "C:\Python27\lib\urllib2.py", line 400, in open
response = meth(req, response)   File "C:\Python27\lib\urllib2.py", line 513, in http_response
'http', request, response, code, msg, hdrs)   File "C:\Python27\lib\urllib2.py", line 438, in error
return self._call_chain(*args)   File "C:\Python27\lib\urllib2.py", line 372, in _call_chain
result = func(*args)   File "C:\Python27\lib\urllib2.py", line 521, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp) HTTPError: HTTP Error 403: Forbidden

感谢您的帮助！

Answer 1

403错误不是来自您的代码，而是来自Google。谷歌让你知道你没有权限访问你请求的资源，在这种情况下是天气API，因为它已经停止（403技术上代表禁止，他们也可能已经去了404 Not Found或410 Gone ）。

有关详情，请参阅http://thenextweb.com/google/2012/08/28/did-google-just-quietly-kill-private-weather-api/

除此之外，您的代码是正确的。

Answer 2

这不是你的错误。谷歌不久前停止了它的天气API。

如果您需要免费天气API，我建议您使用我正在构建的服务Metwit weather API。这是使用metwit-weather：

的最简单的工作示例

from metwit import Metwit
weather = Metwit.weather.get(location_lat=45.45, location_lng=9.18)

此处可以找到更多示例：http://soup.metwit.com/post/45997437810/python-weather-by-metwit

Answer 3

我正在使用Python3并遇到同样的问题。我发现Google会阻止不会覆盖User-Agent和Accept-Encoding标头的urllib。

用于测试搜索的标题：

GET /search?q=f1+2015 HTTP/1.1
Accept-Encoding: identity
Connection: close
User-Agent: Python-urllib/3.4
Host: 127.0.0.1:8076

我把＆＃39; Accept-Encoding＆＃39;到＆＃39;＆＃39;和＆＃39;用户代理＆＃39;去测试＆＃39;并且403错误停止了。

Python HTTP错误403禁止

3 个答案: