Question

我目前正在开发一个wp8.1应用程序C＃，我已经设法通过从textbox.texts创建一个json对象（bm）在json中执行一个POST方法到我的api。这是我的代码如下。我如何使用相同的textbox.text并将它们作为内容类型= application / x-www-form-urlencoded进行POST。该代码是什么？

            Profile bm = new Profile();
            bm.first_name = Names.Text;
            bm.surname = surname.Text;

            string json = JsonConvert.SerializeObject(bm);

            MessageDialog messageDialog = new MessageDialog(json);//Text should not be empty 
            await messageDialog.ShowAsync();

            HttpClient client = new HttpClient();
            client.DefaultRequestHeaders.Clear();
            client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
            client.DefaultRequestHeaders.TryAddWithoutValidation("Content-Type", "application/json");

            byte[] messageBytes = Encoding.UTF8.GetBytes(json);
            var content = new ByteArrayContent(messageBytes);
            content.Headers.ContentType = new MediaTypeHeaderValue("application/json");
            var response = client.PostAsync("myapiurl", content).Result;

Answer 1

var nvc = new List<KeyValuePair<string, string>>();
nvc.Add(new KeyValuePair<string, string>("Input1", "TEST2"));
nvc.Add(new KeyValuePair<string, string>("Input2", "TEST2"));
var client = new HttpClient();
var req = new HttpRequestMessage(HttpMethod.Post, url) { Content = new FormUrlEncodedContent(nvc) };
var res = await client.SendAsync(req);

或者

var dict = new Dictionary<string, string>();
dict.Add("Input1", "TEST2");
dict.Add("Input2", "TEST2");
var client = new HttpClient();
var req = new HttpRequestMessage(HttpMethod.Post, url) { Content = new FormUrlEncodedContent(dict) };
var res = await client.SendAsync(req);

Answer 2

 var params= new Dictionary<string, string>();
 var url ="Please enter URLhere"; 
 params.Add("key1", "value1");
 params.Add("key2", "value2");

 using (HttpClient client = new HttpClient())
  {
        client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));

HttpResponseMessage response = client.PostAsync(url, new FormUrlEncodedContent(dict)).Result;
              var tokne= response.Content.ReadAsStringAsync().Result;
}

//Get response as expected

Answer 3

对我来说最好的解决方案是：

...
import org.springframework.http.ResponseEntity;
...


public ResponseEntity<List<Dto>> search() {
    DtoClient client = DtoClient.connect();
    return client.search();
}

Answer 4

发布此内容类型且不使用字典的另一种变体是：

StringContent postData = new StringContent(JSON_CONTENT, Encoding.UTF8, "application/x-www-form-urlencoded");
using (HttpResponseMessage result = httpClient.PostAsync(url, postData).Result)
{
    string resultJson = result.Content.ReadAsStringAsync().Result;
}

Answer 5

我正在使用具有[FromBody]属性的.Net Core 2.1 API，并且必须使用以下解决方案才能成功将其发布：

_apiClient =  new HttpClient();
_apiClient.BaseAddress = new Uri(<YOUR API>);
var MyObject myObject = new MyObject(){
    FirstName = "Me",
    LastName = "Myself"
};

var stringified = JsonConvert.SerializeObject(myObject);
var result = await _apiClient.PostAsync("api/appusers", new StringContent(stringified, Encoding.UTF8, "application/json"));

Answer 6

您可以这样设置值，并将其发送到PostAsync方法：

var apiClient = new HttpClient();
var values = new Dictionary<object, object>
{
    {"key1", val1},
    {"key2", "val2"}
};

var content = new StringContent(JsonConvert.SerializeObject(values), Encoding.UTF8, "application/json");
var response = await apiClient.PostAsync("YOUR_API_ADDRESS", content);

如何使用HTTPclient内容类型= application / x-www-form-urlencoded进行POST

6 个答案: