直方图特征向量

时间:2017-03-31 13:13:04

标签: java image-processing histogram

我已经制作了这个方法,它获取红色,绿色和蓝色的值并将它们存储在temp int中,然后将该int添加到数组中。我希望在不合并它们的情况下组合这些值,但我不确定如何?

public static double[] GetHistogram (BufferedImage img) {
    double[] myHistogram = new double [256];

    int Temp = 0;
    int Temp1 = 0;
    int Temp2 = 0;

     for (int y = 0; y < img.getHeight(); y += 1)
     {
         for (int x = 0; x < img.getWidth(); x += 1)
         {
              int clr =  img.getRGB(x,y); 

              int  red   = (clr & 0x00ff0000) >> 16;
              int  green = (clr & 0x0000ff00) >> 8;
              int  blue  =  clr & 0x000000ff;

             Temp = 0;
             Temp1 = 0;
             Temp2 = 0; 

            Temp += red;
            Temp1 += green;
            Temp2 += blue;

             Temp = (int) Temp;
             myHistogram[Temp]++;
             myHistogram[Temp1]++;
             myHistogram[Temp2]++;
         }

     }
     return myHistogram;
 }

0 个答案:

没有答案