我想删除具有相同(或类似)时间的记录。这是样本数据:
ID | Name | DateTime
---+------+--------------------
1 | Joe | 2017-03-01 11:33:13
1 | Joe | 2017-03-01 11:33:14
1 | Joe | 2017-03-01 11:33:15
1 | Joe | 2017-03-01 11:55:30
2 | John | 2017-02-15 08:55:48
2 | John | 2017-02-15 08:55:49
2 | John | 2017-02-15 08:56:30
2 | John | 2017-02-15 10:15:40
删除后:
ID | Name | DateTime
---+------+---------------------
1 | Joe | 2017-03-01 11:33:13
1 | Joe | 2017-03-01 11:55:30
2 | John | 2017-02-15 08:55:48
2 | John | 2017-02-15 10:15:40
删除用户的所有相似时间(例如10分钟)
请帮我怎么做。感谢
答案 0 :(得分:3)
CREATE TABLE #TABLE1
([ID] INT, [NAME] VARCHAR(4), [DATETIME] DATETIME)
INSERT INTO #TABLE1
([ID], [NAME], [DATETIME])
VALUES
(1, 'JOE', '2017-03-01 11:33:13'),
(1, 'JOE', '2017-03-01 11:33:14'),
(1, 'JOE', '2017-03-01 11:33:15'),
(1, 'JOE', '2017-03-01 11:55:30'),
(2, 'JOHN', '2017-02-15 08:55:48'),
(2, 'JOHN', '2017-02-15 08:55:49'),
(2, 'JOHN', '2017-02-15 08:56:30'),
(2, 'JOHN', '2017-02-15 10:15:40')
SELECT A.ID,A.NAME,A.[DATETIME] FROM
(SELECT *,ROW_NUMBER() OVER( PARTITION BY ( CAST(CONVERT(CHAR(16), [DATETIME],113) AS DATETIME)) ORDER BY [NAME]) AS RN FROM #TABLE1
)A
WHERE RN=1 ORDER BY ID
输出
ID NAME DATETIME
1 Joe 2017-03-01 11:33:13.000
1 Joe 2017-03-01 11:55:30.000
2 John 2017-02-15 08:55:48.000
2 John 2017-02-15 10:15:40.000