使用SQL查找类似记录

时间:2010-08-11 13:34:00

标签: sql-server tsql

我有一个带有2个表的SQL Server 2008数据库。这些表是地址和存储。这些表定义为

Address
--------
ID (int)
Line1 (nvarchar(255))
PostalCode (nvarchar(5))
City (nvarchar(255))
State (nvarchar(255))

Store
-----
ID (int)
LocationID (int)
Name

我正在尝试找到Line1和PostalCode位于同一地址的商店列表。由于重复记录,我需要忽略ID。我不关心商店是他们所在地唯一的商店。相反,我只想要一个共享位置的商店列表。不幸的是,我不知道该怎么做。

如何编写一个只返回同一Line1和PostalCode的地址记录的查询?

谢谢!

3 个答案:

答案 0 :(得分:3)

这是你想要的吗?

SELECT t1.*, s.* FROM
(SELECT Line1 ,PostalCode
FROM Address
GROUP BY Line1 ,PostalCode
HAVING COUNT(*) >1) t2
JOIN Address t1 ON t2.Line1  = t2.Line1 
AND t1.PostalCode = t2.PostalCode
JOIN  Store s on t1.ID = s.LocationID

答案 1 :(得分:2)

select s.ID, s.LocationID, s.Name, a.ID, a.Line1, a.PostalCode
from (
    select Line1 + ', ' + PostalCode as Line1PostalCode
    from Address a
    inner join Store s on a.ID = s.LocationID
    group by Line1+ ', ' + PostalCode
    having count(*) > 1
) ag
inner join Address a on ag.Line1PostalCode = a.Line1+ ', ' + a.PostalCode
inner join Store s on a.ID = s.LocationID

答案 2 :(得分:0)

此查询使用子查询查找具有多个商店的所有地址,然后将其用作选择要显示的商店的基础。

WITH StoreAddress AS 
(
 SELECT * FROM Store s INNER JOIN Address a ON s.LocationID=a.LocationID
)
SELECT sa.* FROM StoreAddress sa INNER JOIN 
   (SELECT Line1, PostCode FROM StoreAddress
   GROUP BY Line1, PostCode
   HAVING Count(ID)>1) pairs 
ON pairs.Line1=sa.Line1 AND pairs.PostCode=sa.PostCode
ORDER BY sa.Line1, sa.PostCode

查询按Line1和PostCode排序,以便同一位置的存储一起显示。