我有一个类似下面示例的查询,我希望从包含4列的表中使用连接动态批量收集2列,但我不断收到错误,该变量不在选择列表中#39 ;。我相信这是因为这是因为查询的列数比表格少,但我不知道如何绕过它。
DECLARE
TYPE test_table_type IS TABLE OF TEST_PRODUCTS%ROWTYPE;
BULK_COLLECTOR test_table_type;
BEGIN
EXECUTE IMMEDIATE
'SELECT tp.PRODUCT AS PRODUCT, td.ALT_DESCRIPTION AS DESCRIPTION
FROM TEST_PRODUCTS tp
JOIN ALT_DESCRIPTIONS td ON tp.ALT_DESCRIPTION_ID = td.ALT_DESCRIPTION_ID'
BULK COLLECT INTO BULK_COLLECTOR;
END;
以下是表格的示例:
CREATE TABLE TEST_PRODUCTS
(
PRODUCT_ID NUMBER,
PRODUCT VARCHAR2(50),
DESCRIPTION VARCHAR2(255)
ALT_DESCRIPTION_ID NUMBER,
INVENTORY_CODE VARCHAR2(100)
);
CREATE TABLE ALT_DESCRIPTIONS
(
ALT_DESCRIPTION_ID NUMBER,
ALT_DESCRIPTION VARCHAR2(255)
);
答案 0 :(得分:3)
您正在从两个不同的表中进行选择,并尝试将其放入一个表的行类型中。
你可能想采取不同的方法 - 像这样:
DECLARE
TYPE test_record IS RECORD
(
PRODUCT VARCHAR2(50),
ALT_DESCRIPTION VARCHAR2(255)
);
type test_tab is table of test_record;
BULK_COLLECTOR test_tab;
BEGIN
EXECUTE IMMEDIATE
'SELECT tp.PRODUCT AS PRODUCT, td.ALT_DESCRIPTION AS DESCRIPTION
FROM TEST_PRODUCTS tp
JOIN ALT_DESCRIPTIONS td ON tp.ALT_DESCRIPTION_ID = td.ALT_DESCRIPTION_ID'
BULK COLLECT INTO BULK_COLLECTOR;
END;