Question

如果它真的是“行首+可选空格+测试+空格”，如何只从大字符串中解释特定单词（例如test）。还允许单词'test'的混合大小写

Answer 1

对所有参数使用REGEXP_REPLACE，你可以......

提供您想要影响的价值
提供您要查找的正则表达式
告诉函数启动什么字符
告诉功能您想要替换的事件
提供其他修饰符，其中“i”表示使用不区分大小写

如果您要删除第二个测试实例，或TeSt或TEST，这将有效。你没有提供很多例子和预期结果。

-- Start test data
with test_data as
    (select 'TeSt this is how I am going to tEst going for' as test_string from dual union all
     select 'test hello everyone how are you test' from dual union all
     select 'test_find1();' from dual union all
     select 'test sample 1;' from dual union all
     select 'TEST sample 2;' from dual union all
     select 'test1 hope this is will help test2;' from dual)
-- End test data     
select test_string,
       CASE WHEN REGEXP_LIKE(test_string,'^test\s+','i') THEN
                    REGEXP_REPLACE(test_string,'test','', 1, 2, 'i')
           ELSE NULL END AS result
from   test_data;

有关REGEXP_REPLACE here

Answer 2

我正在使用您输入的字符串，如下所示

'    TeSt this is how I am going to tEst going for '

并故意在开头和结尾保留一些空格。下面的代码生成您想要的输出。另外，正如您所提到的，它将替换TEST一词的所有实例而不考虑大小写。我希望这会有所帮助。

  Select 
REGEXP_REPLACE(     --Using RegExp_replace
    ltrim(rtrim(    --Trimming the white spaces
        input1)),   --using the input
        'TEST',     --search criteria
        '',         --Replace with string
        2,          --Starting with which character (you mentioned first occerance should remain
        0,          --Replace all subsequent occurances
        'i')        --case in-sensitive
        from (
Select '    TeSt this is how I am going to tEst going for' as input1 from dual --this is your INPUT)

谢谢，桑托什

PL SQL模式匹配

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